.filter() 数组使用另一个数组的元素 [英] .filter() array using another array's elements

问题描述

我有一系列人的名字以及他们的语言知识.我想要做的是将过滤器传递到语言列并过滤掉任何不匹配的结果.

I have an array of people's names along with their knowledge of languages. What I want to do is pass a filter onto the language column and filter out any results that don't match.

这是样本数组

   var myArray = [["Steppen", "Spanish Polish"],
                  ["Wolf", "Spanish Polish Tagalog"],
                  ["Amanda", "Spanish"],
                  ["Ada", "Polish"],
                  ["Rhonda", "Spanish Tagalog"]];

就传递过滤器而言，它可以是一种语言或多种语言.即使过滤器中的一种语言匹配 - 也应该返回结果.因此，例如，应返回他加禄语"过滤器 - Wolf 和 Rhonda.西班牙语波兰语"过滤器应该返回每个人 - 有西班牙语或波兰语的匹配项.

As far as passing in filters, it could be either one language or many. Even if one language from a filter matches - the result should be returned. So for example, a filter of "Tagalog" should return - Wolf and Rhonda. A filter of "Spanish Polish" should return everyone - there's either a match in Spanish or Polish.

我编写了过滤器函数，但由于某种原因它卡住了，当我通过过滤器他加禄语"时，它只会迭代到数组中的第二个单元格(西班牙波兰他加禄语)并重复多次而不是前进.

I wrote the filter function but for some reason it's getting stuck, when I pass the filter "Tagalog" it only iterates to the second cell in the array (Spanish Polish Tagalog) and repeats itself multiple times instead of going forward.

我做错了什么，我应该以不同的方式迭代吗?

What am I doing wrong, should I be iterating differently?

 var userPassedFilter = new Array();
 userPassedFilter[0] = "Tagalog";

 newArray = consolidatedFilters(myArray, userPassedFilter);
 console.log(newArray);

 function consolidatedFilters(passedArray, passedFilter)
 {
 var filteredArray = passedArray.filter(    
    function(el)
    {
        for (var i = 0; i < passedArray.length; i++)
         {
            console.log("i is " + i);
             for (var j in passedFilter)
            {
                console.log("Passed Filter j " + passedFilter[j]);
                console.log("Passed Array  i " + passedArray[i][1]);        
                console.log("String Search " + passedArray[i][1].search(passedFilter[j]));

                if (passedArray[i][1].search(passedFilter[j]) != -1)
                {
                    return true;
                }
            }           
        }
         return false;
    }
 );     
 return filteredArray;
 }

推荐答案

在我看来，你让它变得有点太复杂了.

To me it seems like you're making it a little too complicated.

1. 迭代 3 次(filter、for 循环、for in 循环).
2. 对数组使用 for in 循环.
3. 同时使用 new Array 和 [...].

1. Iterating three times (filter, for loop, for in loop).
2. Using a for in loop for an array.
3. Using both new Array and [...].

我更新了一点，看起来这就是你想要的:http://jsfiddle.net/pimvdb/RQ6an/.

I updated it a little and it looks like this is what you want: http://jsfiddle.net/pimvdb/RQ6an/.

var myArray = [["Steppen", "Spanish Polish"],
              ["Wolf", "Spanish Polish Tagalog"],
              ["Amanda", "Spanish"],
              ["Ada", "Polish"],
              ["Rhonda", "Spanish Tagalog"]];

var userPassedFilter = ["Tagalog"];

newArray = consolidatedFilters(myArray, userPassedFilter);
console.log(newArray);

function consolidatedFilters(passedArray, passedFilter) {
    var filteredArray = passedArray.filter(
    function(el) { // executed for each person
        for (var i = 0; i < passedFilter.length; i++) { // iterate over filter
            if (el[1].indexOf(passedFilter[i]) != -1) {
                return true; // if this person knows this language
            }
        }
        return false;
    }
    );     
    return filteredArray;
}

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