函数参数中 int * array 和 int array[] 的区别 [英] Difference between int * array and int array[] in a function parameter

问题描述

我已经看到如果函数参数是int arr[]"或int * arr"，数组值会发生变化.区别在哪里?

I have seen that the array values ​​will change if the function parameter is "int arr[]" or "int * arr". Where is the difference?

整数数组[]:

void myFunction(int arr[], int size) {

    for (int i = 0; i < size; ++i)
        arr[i] = 1;
}

int * 数组:

void myFunction(int * arr, int size) {

    for (int i = 0; i < size; ++i)
        arr[i] = 1;
}

两个函数都会改变数组值.

Both functions change the array values.

int main(){

     int array[3];

     array[0] = 0;
     array[1] = 0;
     array[2] = 0;

     myFunction(array, 3);

     return 0;

 }

推荐答案

没有区别.两种函数类型(调整后)都是函数采用指向 int 和 int 的指针，返回 void".这只是 C++ 的一个语法怪癖:非引用类型的函数参数中最外层的 [] 与 * 同义.

There is no difference. Both functions types (after adjustment) are "function taking a pointer to int and an int, returning void." This is just a syntactic quirk of C++: the outermost [] in a function parameter of non-reference type is synonymous with *.

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