如何传递一个临时数组? [英] How to pass a temporary array?
问题描述
如何传递临时数组?我想做这样的事情:
How can I pass a temporary array? I want to do something like this:
#include <iostream>
int sum(int arr[]) {
int answer = 0;
for (const auto& i : arr) {
answer += i;
}
return answer;
}
int main() {
std::cout << sum( {4, 2} ) << std::endl; // error
std::cout << sum( int[]{4, 2} ) << std::endl; // error
}
在函数参数的大括号 []
中是否需要正整数文字?如果我包含那个文字,它会限制我只能传递给那个大小的数组的数组吗?另外,如何通过右值引用或常量引用传递数组元素?由于上述示例无法编译,因此我认为使函数的参数类型 int&&[]
或 const int&[]
不起作用.
Do I need a positive integer literal in the function parameter's braces []
? If I include that literal, will it limit what arrays I can pass to only arrays of that size? Also, how can I pass array elements by rvalue reference or const reference? Because the above sample doesn't compile, I presume making the function's parameter type int&&[]
or const int&[]
won't work.
推荐答案
首先,您不能将数组作为纯右值传递,因此您的函数需要引用.其次,数组的大小是类型的一部分,因此您的函数可能需要成为模板的一部分.第三,编写临时数组在词汇上有点傻,所以你需要一些噪音.
First off, you cannot pass arrays as prvalues, so your function needs to take a reference. Second, the size of the array is part of the type, so your function probably needs to be part of a template. Third, writing array temporaries is lexically a bit silly, so you need some noise.
综合起来,以下应该可以工作
Putting it all together, the following ought to work
template <std::size_t N>
int sum(const int (&a)[N])
{
int n = 0;
for (int i : a) n += i;
return n;
}
int main()
{
std::cout << sum({1, 2, 3}) << "\n";
}
int main()
{
using X = int[3];
std::cout << sum(X{1, 2, 3}) << "\n";
}
句法噪音可以用别名模板稍微概括:
The syntactic noise can be generalized slightly with an alias template:
template <std::size_t N> using X = int[N];
用法:sum(X<4>{1, 2, 3, 4})
(您不能从初始化程序推导出模板参数.) 感谢 Jarod42 指出实际上完全有可能从花括号列表中推导出模板参数;不需要类型别名.
Usage: sum(X<4>{1, 2, 3, 4})
(You cannot have the template parameter deduced from the initializer.) Thanks to Jarod42 for pointing out that it is in fact perfectly possible to deduce the template argument from a braced list; no type alias is needed.
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