“int *a[5]"和“int *a[5]"有什么区别?和 int(*a)[5]"? [英] What's the difference between "int *a[5]" and int(*a)[5]"?

问题描述

它们在 C 和 C++ 上的工作方式会不同吗?

Would they work differently on C and C++?

推荐答案

1. int *a[5] -这意味着a"是一个指针数组，即数组a"中的每个成员都是一个指针
   整数类型；数组的每个成员都可以保存一个整数的地址.

1. int *a[5] - It means that "a" is an array of pointers i.e. each member in the array "a" is a pointer
   of type integer; Each member of the array can hold the address of an integer.

int (*a)[5] -这里的a"是指向 5 个整数数组的指针，换句话说a"指向一个包含 5 个整数的数组.

int (*a)[5] - Here "a" is a pointer to the array of 5 integers, in other words "a" points to an array that holds 5 integers.

示例:

#include<stdio.h>
   int main()
   {
           int b = 3;
           int c = 4;
           int *a[2] = {&b, &c}; // is same as ---int *a[] = {&b, &c} 
           printf("value pointed to by a[0] = %d, by a[1] = %d\n", *a[0], *a[1]);
           return 0;
   }

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