Javascript Arrays - 检查两个对象数组的相同内容，忽略顺序 [英] Javascript Arrays - Checking two arrays of objects for same contents, ignoring order

问题描述

我有两个 JavaScript 数组(A 和 B)，其中包含我创建的对象.我想检查数组 A 中的所有对象是否包含在数组 B 中，但顺序不一定相同.

I have two JavaScript arrays (A and B) that contain objects that I created. I want to check that all the objects in array A are contained in array B, but not necessarily in the same order.

最好的方法是什么?

它们都是实际的对象，而不是基元，所以我还需要比较它们的内容和结构(可能使用类似 JSON.stringify 的东西).

They are all actual objects, not primitives, so I will need to compare their contents and structure as well (maybe using something like JSON.stringify).

我想这样做是因为我正在学习测试驱动开发，并且我想测试返回对象列表的函数.我需要测试返回的列表中是否包含预期的对象(在这种情况下顺序无关紧要).

I want to do this because I'm learning Test-Driven Development, and I want to test functions that return lists of objects. I need to test whether the returned lists have the expected objects in them or not (order doesn't matter in this case).

推荐答案

用法: isEqArrays(arr1, arr2)

//
// Array comparsion
//

function inArray(array, el) {
  for ( var i = array.length; i--; ) {
    if ( array[i] === el ) return true;
  }
  return false;
}

function isEqArrays(arr1, arr2) {
  if ( arr1.length !== arr2.length ) {
    return false;
  }
  for ( var i = arr1.length; i--; ) {
    if ( !inArray( arr2, arr1[i] ) ) {
      return false;
    }
  }
  return true;
}

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