java - 如何将大型二进制字符串转换为字节数组java? [英] How do I convert a large binary String to byte array java?

问题描述

我有一个很大的二进制字符串101101110..."，我试图将它存储到一个字节数组中.最好的方法是什么?

I have a large binary string "101101110...", and I am trying to store it into a byte array. what is the best way of doing it?

假设我有 largeString = "0100111010111011011000000001000110101"

Lets say I have largeString = "0100111010111011011000000001000110101"

我正在寻找的结果:

[78, 187, 96, 17, 21]

[78, 187, 96, 17, 21]

01001110 10111011 01100000 00010001 10101

01001110 10111011 01100000 00010001 10101

我尝试过的:

byte[] b= new BigInteger(largeString,2).toByteArray();

但是它没有给我我正在寻找的结果......

however it did not give me the result I'm looking for...

推荐答案

你可以很容易地构建一个 ArrayList，如果你想要一个实际的数组，你可以在它上面调用 toArray；

You can easily build an ArrayList on which you can call toArray if you want an actual array;

List<Integer> list = new ArrayList<>();

for(String str : largeString.split("(?<=\\G.{8})"))
    list.add(Integer.parseInt(str, 2));

System.out.println(list);  // Outputs [78, 187, 96, 17, 21]

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