如何将 VLA 传递给函数模板? [英] How to pass a VLA to a function template?

问题描述

我有以下代码无法编译.

I have the following code which could not be complied.

using namespace std;
void f(int);
template<typename T1, size_t N>
void array_ini_1d(T1 (&x)[N])
{
  for (int i = 0; i < N; i++)
  {
    x[i] = 0;
  }
}

如果主要内容如下所示，传递数组的正确方法是什么.

What is the proper way to pass the array if the main is something like below.

int main()
{
  int a;
  cin >> a;
  int n = a / 4;
  f(n);
  return 0;
}

void f(int n)
{
  int arr[n];
  array_ini_1d(arr);
}

错误:没有匹配的函数来调用array_ini_1d........

error: no matching function to call to array_ini_1d..............

推荐答案

我认为编译器无法推断出模板中变长数组的大小.另外，在使用之前不要忘记转发声明 f.可变长度数组是 GCC 扩展，您应该收到有关其使用的警告.

I don't think the compiler can deduce the size of a variable-length array in a template. Also, don't forget to forward declare f before you use it. Variable-length arrays are a GCC extension and you should get a warning regarding their use.

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