C++ 从数字数组创建 png/位图 [英] C++ create png/bitmap from array of numbers

问题描述

所以我找到了关于我的问题的链接，但它是针对 c# 的

用于转换和放大的 ImageMagick 命令是这样的:

convert image.ppm -scale 400x result.png

如果 ImageMagick 有点重量级，或者难以安装，您可以更简单地使用 NetPBM 工具(来自 此处) 像这样(它是一个单独的预编译二进制文件)

pnmtopng image.ppm >结果.png

So i found this link regarding my question, but it is for c#

Create a PNG from an array of bytes

I have a variable int array of numbers. i will call it "pix[ ]" for now it can be any size from 3 to 256, later possibly bigger.

What i want to do now, is to convert it into a pixel image. I am still a noobin c++ so pleas excuse me. I tried to download some libaries that make working with libpng easier, but they do not seem to be working (ubuntu, code::blocks) So i have questions in the following:

1) how do you create a new bitmap (which libaries, which command)?

2) how do i fill it with information from "pix[ ]" ?

3) how do i save it?

if it is a repost of a question i am happy about a link also ;)

Here is what i worked out so far, thanks for your help.

int main(){
 FILE *imageFile;
 int x,y,pixel,height=2,width=3;

 imageFile=fopen("image.pgm","wb");
 if(imageFile==NULL){
  perror("ERROR: Cannot open output file");
  exit(EXIT_FAILURE);
 }

 fprintf(imageFile,"P3\n");           // P3 filetype
 fprintf(imageFile,"%d %d\n",width,height);   // dimensions
 fprintf(imageFile,"255\n");          // Max pixel
  int pix[100] {200,200,200, 100,100,100, 0,0,0, 255,0,0, 0,255,0, 0,0,255};


       fwrite(pix,1,18,imageFile);


fclose(imageFile);
}

i have not fully understood what it does. i can open the output image, but it is not a correct representation of the Array.

If i change things around, for example making a 2 dimensional array, then the image viewer tells me "expected an integer" and doesn't show me an image.

So far so good. As i have the array before the image i created a function aufrunden to round up to the next int number because i want to create a square image.

int aufrunden (double h)
{
int i =h;
if (h-i == 0)
  {
  return i;
  }
else
  {
  i = h+1;
  return i;
  }
}

This function is used in the creation of the image. If the image is bigger than the information the array provides like this (a is the length of th array)

double h;
h= sqrt(a/3.0);
int i = aufrunden(h);
FILE *imageFile;                           
int height=i,width=i;

It might happen now, that the array is a=24 long. aufrunden makes the image 3x3 so it has 27 values...meaning it is missing the values for 1 pixel. Or worse it is only a=23 long. also creating a 3x3 image.

What will fwrite(pix,1,18,imageFile); write in those pixels for information? It would be best if the remaing values are just 0.

*edit never mind, i will just add 0 to the end of the array until it is filling up the whole square...sorry

解决方案

Consider using a Netpbm format (pbm, pgm, or ppm).

These images are extremely simple text files that you can write without any special libraries. Then use some third-party software such as ImageMagick, GraphicsMagick, or pnmtopng to convert your image to PNG format. Here is a wiki article describing the Netpbm format.

Here's a simple PPM image:

P3 2 3 255
0 0 0       255 255 255
255 0 0     0 255 255
100 100 100 200 200 200

The first line contains "P3" (the "magic number identifying it as a text-PPM), 2 (width), 3 (height), 255 (maximum intensity). The second line contains the two RGB pixels for the top row. The third and fourth lines each contain the two RGB pixels for rows 2 and 3.

Use a larger number for maximum intensity (e.g. 1024) if you need a larger range of intensities, up to 65535.

Edited by Mark Setchell beyond this point - so I am the guilty party!

The image looks like this (when the six pixels are enlarged):

The ImageMagick command to convert, and enlarge, is like this:

convert image.ppm -scale 400x result.png

If ImageMagick is a bit heavyweight, or difficult to install you can more simply use the NetPBM tools (from here) like this (it's a single precompiled binary)

pnmtopng image.ppm > result.png

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