从 C++ 中的现有数组创建子数组的最佳方法是什么? [英] What is the best way to create a sub array from an exisiting array in C++?

问题描述

好的，我正在尝试从现有数组中获取子数组，但我不知道该怎么做.在我的示例中，我有一个非常大的数组，但我想从数组的最后 5 个元素创建一个数组.

OK, I am trying to get a sub array from an existing array and I'm just not sure how to do it. In my example I have a very large array, but I want to create an array from the last 5 elements of the array.

我正在谈论的一个例子是:

An example of what I am talking about would be:

int array1 = {1,2,3,...99,100};
int array2[5] = array1+95;

我知道这不正确，但我在正确处理时遇到了一些麻烦.我想在 array1 中获取元素 96 到 100 并将它们放入 array2 但我不想复制数组.我只希望 array2 从 96 元素开始，这样 array1[96] 和 array2[0] 将指向相同的位置.

I know this isn't correct, but I am having some trouble getting it right. I want to get the elements 96 through 100 in array1 and put them into array2 but I don't want to copy the arrays. I just want array2 to start at the 96 element such that array1[96] and array2[0] would be pointing to the same location.

推荐答案

为此:

"such that array1[96] and array2[0] would be pointing to the same location."

你可以:

int *arr2 = arr1 + 96;
assert(arr2[0] == arr1[96] == 97);

这篇关于从 C++ 中的现有数组创建子数组的最佳方法是什么?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！