通过其 ID 序列化 JAXB 对象? [英] Serialize a JAXB object via its ID?

问题描述

在我的数据模型中，我有这样的效果:

In my data model, I have something to this effect:

@Entity
public class Target {

    @Id 
    @GeneratedValue
    private Long id;

    /* ...etc... */
}

@Entity
public class Dependency {

    @Id
    @GeneratedValue
    private Long id;

    @ManyToOne(optional=false)
    @Column(name="target_id")
    private Target target;

    /* ...etc... */
}

我已经很好地序列化了 Target，但是我需要序列化 ​​Dependency.基本上，我需要的是这样的:

I'm already serializing Target just fine, but I need to serialize Dependency. Essentially, what I need is something like this:

<dependency>
    <id>100</id>
    <targetId>200</targetId>
</dependency>

有没有办法在不修改我的模型的情况下在 JAXB 注释中做到这一点?

Is there a way to do this in JAXB annotations without modifying my model?

推荐答案

对于这个用例，您可以使用 XmlAdapter:

You could use an XmlAdapter for this use case:

package forum7278406;

import javax.xml.bind.annotation.adapters.XmlAdapter;

public class TargetAdapter extends XmlAdapter<Long, Target> {

    @Override
    public Long marshal(Target target) throws Exception {
        return target.getId();
    }

    @Override
    public Target unmarshal(Long id) throws Exception {
        Target target = new Target();
        target.setId(id);
        return target;
    }

}

XmlAdapter 使用 @XmlJavaTypeAdapter 注释注册在 Dependency 类上:

The XmlAdapter is registered on the Dependency class using the @XmlJavaTypeAdapter annotation:

package forum7278406;

import javax.persistence.*;
import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@Entity
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Dependency {

    @Id
    @GeneratedValue
    private Long id;

    @ManyToOne(optional=false)
    @Column(name="target_id")
    @XmlJavaTypeAdapter(TargetAdapter.class)
    private Target target;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public Target getTarget() {
        return target;
    }

    public void setTarget(Target target) {
        this.target = target;
    }

}

---

走得更远

我们可以使用 EntityManager 从数据库中查询相应的实例，而不是仅仅创建 Target 的新实例.我们的 XmlAdapter 将更改为如下所示:

Instead of just creating a new instance of Target we could use an EntityManager to query the corresponding instance from the database. Our XmlAdapter would be changed to look something like:

package forum7278406;

import javax.persistence.EntityManager;
import javax.xml.bind.annotation.adapters.XmlAdapter;

public class TargetAdapter extends XmlAdapter<Long, Target> {

    EntityManager entityManager;

    public TargetAdapter() {
    }

    public TargetAdapter(EntityManager entityManager) {
        this.entityManager = entityManager;
    }

    @Override
    public Long marshal(Target target) throws Exception {
        return target.getId();
    }

    @Override
    public Target unmarshal(Long id) throws Exception {
        Target target = null;
        if(null != entityManager) {
            target = entityManager.find(Target.class, id);
        }
        if(null == target) {
            target = new Target();
            target.setId(id);
        }
        return target;
    }

}

现在要在我们的 XmlAdapter 上设置 EntityManager 的实例，我们可以执行以下操作:

Now to set the instance of EntityManager on our XmlAdapter, we can do the following:

Unmarshaller umarshaller = jaxbContext.createUnmarshaller();
TargetAdapter targetAdatper = new TargetAdapter(entityManager);
unmarshaller.setAdapter(targetAdapter);

这篇关于通过其 ID 序列化 JAXB 对象?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！