如何告诉 JAXB 元素的顺序无关紧要? [英] How to tell JAXB that order of elements does not matter?

问题描述

是否可以告诉 JAXB 忽略元素的顺序?这样生成的 XSD 将包含 all-elements 而不是 sequence-elements?

Is it possible to tell JAXB to ignore the order of elements? So that the generate XSD will contain all-elements instead of sequence-elements?

推荐答案

添加 XmlType 注释到带有空 propOrder 的类，如下所示:

Add an XmlType annotation to the class with an empty propOrder, like this:

@XmlType(propOrder={})
public class MyClass{
    String username;
    String street;
    String address;
}

然后它会生成一个 xs:all(它是无序的)而不是一个序列.

It will then generate an xs:all (which is unordered) instead of a sequence.

<xs:complexType name="MyClass">
  <xs:all>
    <xs:element name="username" type="xs:string" minOccurs="0"/>
    <xs:element name="street" type="xs:string" minOccurs="0"/>
    <xs:element name="address" type="xs:string" minOccurs="0"/>
  </xs:all>
</xs:complexType>

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