正则表达式用于某些顺序无关紧要的单词的存在 [英] Regex for existence of some words whose order doesn't matter

问题描述

我想编写一个正则表达式来搜索某些单词的存在，但是它们的出现顺序无关紧要.

I would like to write a regex for searching for the existence of some words, but their order of appearance doesn't matter.

例如，搜索"Tim"和"stupid".我的正则表达式是Tim.*stupid|stupid.*Tim.但是是否可以编写一个更简单的正则表达式(例如，使两个单词在正则表达式本身中仅出现一次)?

For example, search for "Tim" and "stupid". My regex is Tim.*stupid|stupid.*Tim. But is it possible to write a simpler regex (e.g. so that the two words appear just once in the regex itself)?

推荐答案

参见此正则表达式:

/^(?=.*Tim)(?=.*stupid).+/

正则表达式说明:

• ^在字符串开头声明位置.
• (?=.*Tim)断言字符串中存在"Tim".
• (?=.*stupid)断言字符串中存在愚蠢".
• .+现在存在我们的短语，此字符串有效.继续并使用.+或-.++来匹配整个字符串.

• ^ Asserts position at start of string.
• (?=.*Tim) Asserts that "Tim" is present in the string.
• (?=.*stupid) Asserts that "stupid" is present in the string.
• .+Now that our phrases are present, this string is valid. Go ahead and use .+ or - .++ to match the entire string.

要更专门地使用前瞻，可以添加另一个(?=.*<to_assert>)组.整个正则表达式可以简化为/^(?=.*Tim).*stupid/.

To use lookaheads more exclusively, you can add another (?=.*<to_assert>) group. The entire regex can be simplified as /^(?=.*Tim).*stupid/.

请参见正则表达式演示！

>>> import re
>>> str ="""
... Tim is so stupid.
... stupid Tim!
... Tim foobar barfoo.
... Where is Tim?"""
>>> m = re.findall(r'^(?=.*Tim)(?=.*stupid).+$', str, re.MULTILINE)
>>> m
['Tim is so stupid.', 'stupid Tim!']
>>> m = re.findall(r'^(?=.*Tim).*stupid', str, re.MULTILINE)
>>> m
['Tim is so stupid.', 'stupid Tim!']

了解更多信息

• 带有排除字符和另一个正则表达式的正则表达式

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