是否存在与包含数组的对象无关的简单匹配，而数组内容的顺序无关紧要? [英] Is there a simple match for objects containing array where the array content order doesn't matter?

问题描述

当我不在乎键的顺序或数组内容的顺序时，我试图比较包含数组的对象.包含很深的内容与我需要的内容非常接近，只是我需要同时使用这两种方式来确保数据中没有缺失的元素.理想情况下，我需要一个不区分顺序的 == 版本.我下面有什么更好的选择吗?

I was trying to compare objects that contain arrays when I don't care about the order of keys or the order of array contents. Contains deep is close to what I need except that I need to use it both ways around to ensure there are no missing elements in the data. Ideally I want a version of == that is order-insensitive. Is there is a better option to what I have below?

    * def sample = { user: ['read', 'write', 'append'], public: ['read', 'append'] }
    * def test = { public: ['append', 'read'], user: ['write', 'read', 'append'] }
    * match sample contains deep test
    * match test contains deep sample

推荐答案

仅使用2个包含.是的，我们还没有设计深层容器，很少需要.

Use 2 contains only. Yes we haven't designed a deep contains, it is rarely needed.

* def sample = { user: ['read', 'write', 'append'], public: ['read', 'append'] }
* match sample.public contains only ['append', 'read']
* match sample.user contains only ['write', 'read', 'append']

为了完整起见，尽管除非您想重新使用架构片段，否则这可能是过大的，但是您可以这样做:

For completeness, although this may be overkill unless you want to re-use schema pieces, you can do this:

* def user = ['write', 'read', 'append']
* def public = ['append', 'read']

* def sample = { user: ['read', 'write', 'append'], public: ['read', 'append'] }
* match sample == { user: '#(^^user)', public: '#(^^public)' }

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