如何将二维向量传递给 C++ 中的函数? [英] How to pass 2-D vector to a function in C++?

问题描述

如果是传递，是值传递还是引用传递?

If it is passed, is it passed by value or by reference?

void printMatrix(vector<vector<int>> *matrix);

...

vector<vector<int>> matrix(3, vector<int>(3,0));
printMatrix(&matrix1);

推荐答案

自从你的函数声明:

void printMatrix(vector< vector<int> > *matrix)

指定一个指针，它本质上是通过引用传递的.但是，在 C++ 中，最好避免使用指针并直接传递引用:

specifies a pointer, it is essentially passed by reference. However, in C++, it's better to avoid pointers and pass a reference directly:

void printMatrix(vector< vector<int> > &matrix)

和

printMatrix(matrix1); // Function call

这看起来像一个普通的函数调用，但它是通过引用传递的，如函数声明中所示.这可以避免不必要的指针取消引用.

This looks like a normal function call, but it is passed by reference as indicated in the function declaration. This saves you from unnecessary pointer dereferences.

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