将 txt 文件值存储到二维数组中 [英] Store txt file values into 2D array

问题描述

首先，这是我的代码http://pastebin.com/BxpE7aFA.

现在.我想阅读一个看起来像这样的文本文件 http://pastebin.com/d3PWqSTV并将所有这些整数放入一个名为 level 的数组中.level 的大小为 100x25，在顶部声明.

Now. I want to read a text file which looks like this http://pastebin.com/d3PWqSTV and put all those integers into an array, called level. level has a size of 100x25, which is declared at the top.

我现在唯一的问题是你在哪里看到???.如何从文件中获取字符，并将其放入 level[i][j]?

My only problem now is where you see the ???. How do I get the char from the file, and put that into level[i][j]?

推荐答案

检查矩阵初始化的代码，应该是int level[HEIGHT][WIDTH];不是intlevel[WIDTH][HEIGHT]; 还有，你的数据行比 WIDTH 短.代码的工作方式如下:我们遍历一个级别矩阵的所有行，通过 (file >> row) 指令从文件中读取一行，如果读取成功，那么我们填充行在一个级别矩阵中，否则我们会读取 EOF 从而中断循环.

Check the code of initialization of a matrix, it should be int level[HEIGHT][WIDTH]; not int level[WIDTH][HEIGHT]; also, your data rows are shorter than WIDTH. The code works the next way: we loop through all lines of a level matrix, read a row from a file by (file >> row) instruction, if read was successfull, then we populate row in a level matrix, otherwise we read EOF so break from loop.

    #include<iostream>
    #include<fstream>
    #include<string>
    #include <limits>

    static const int WIDTH = 100;
    static const int HEIGHT = 25;

    int main()
    {
        int level[HEIGHT][WIDTH];

        for(int i = 0; i < HEIGHT; i++)
        {
            for(int j = 0; j < WIDTH; j++)
            {
                level[i][j] = 0;
            }
        }

        std::ifstream file("Load/Level.txt");
        for(int i = 0; i < HEIGHT; i++)
        {
            std::string row;
            if (file >> row) {
                for (int j = 0; j != std::min<int>(WIDTH, row.length()) ; ++j)
                {
                    level[i][j] = row[j]-0x30;
                }
                std::cout << row << std::endl;
            } else break;
        }

        return 0;
    }

这篇关于将 txt 文件值存储到二维数组中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！