如何在 C# 中启动 32 位进程而不在 64 位机器上使用 shell 执行? [英] How to start a 32-bit process in C# without using shell execute on 64-bit machine?
问题描述
我在 64 位计算机上有一个 ASP .NET Web 应用程序,需要运行旧的 32 位报告应用程序.
I have an ASP .NET web application on a 64-bit machine that needs to run a legacy 32-bit reporting application.
当我使用 UseShellExecute = false
运行程序时,程序以退出代码退出:
When I run the program with UseShellExecute = false
, the program exits with exit code:
-1073741502
我无法使用 Shell Execute,因为我必须以不同的用户身份运行该进程.然而,当 Shell Execute 为 true 时,该进程将运行良好(尽管我必须更改 ASP .NET 在其下执行的用户).
I can't use Shell Execute because I have to run the process as a different user. Yet, when Shell Execute is true, the process will run fine (although I have to change the user that ASP .NET is executing under).
如何在不使用 shell 执行的情况下使用 C# 启动这个 32 位程序?
How can I start this 32-bit program using C# without use shell execute?
这是我现在拥有的代码:
Here's the code I have right now:
var pxs = new ProcessStartInfo
{
Arguments = arguments,
CreateNoWindow = true,
Domain = ConfigurationManager.AppSettings["reportUserDomain"],
UserName = ConfigurationManager.AppSettings["reportUserName"],
Password = GetSecureString(ConfigurationManager.AppSettings["reportUserPassword"]),
LoadUserProfile = true,
FileName = ConfigurationManager.AppSettings["reportRuntime"],
UseShellExecute = false
};
var px = new Process
{
StartInfo = pxs
};
px.Start();
px.WaitForExit();
推荐答案
如果您使用 Windows 原生LogonUser"方法包围您的代码,包括 UseShellExecute = true
会怎样?我已经在一些项目中成功地使用了它来做类似的.
What if you surrounded your code, including UseShellExecute = true
, with the windows native "LogonUser" method? I've used this successfully in a few projects to do something similar.
[DllImport("advapi32.dll", CharSet = CharSet.Auto)]
public static extern bool LogonUser(String lpszUserName, String lpszDomain,
String lpszPassword, int dwLogonType, int dwLogonProvider, ref IntPtr phToken
Fresh Click Media 写了一篇关于这个的文章并写了一个模拟类示例:--> http://www.freshclickmedia.com/blog/2008/11/programmatic-impersonation-in-c/
Fresh Click Media did an article about this and wrote a sample Impersonate class: --> http://www.freshclickmedia.com/blog/2008/11/programmatic-impersonation-in-c/
但为了完整起见,这是我的版本:
But for completeness, here's my version of it:
public class Impersonator : IDisposable
{
private WindowsImpersonationContext _impersonatedUser = null;
private IntPtr _userHandle;
// constructor for a local account. username and password are arguments.
public Impersonator(string username, string passwd)
{
_userHandle = new IntPtr(0);
string user = username;
string userDomain = "."; // The domain for a local user is by default "."
string password = passwd;
bool returnValue = LogonUser(user, userDomain, password, LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, ref _userHandle);
if (!returnValue)
throw new ApplicationException("Could not impersonate user");
WindowsIdentity newId = new WindowsIdentity(_userHandle);
_impersonatedUser = newId.Impersonate();
}
// constructor where username, password and domain are passed as parameters
public Impersonator(string username, string passwd, string domain)
{
_userHandle = new IntPtr(0);
string user = username;
string userDomain = domain;
string password = passwd;
bool returnValue = LogonUser(user, userDomain, password, LOGON32_LOGON_INTERACTIVE, LOGON32_PROVIDER_DEFAULT, ref _userHandle);
if (!returnValue)
throw new ApplicationException("Could not impersonate user");
WindowsIdentity newId = new WindowsIdentity(_userHandle);
_impersonatedUser = newId.Impersonate();
}
public void Dispose()
{
if (_impersonatedUser != null)
{
_impersonatedUser.Undo();
CloseHandle(_userHandle);
}
}
public const int LOGON32_LOGON_INTERACTIVE = 2;
public const int LOGON32_LOGON_SERVICE = 3;
public const int LOGON32_PROVIDER_DEFAULT = 0;
[DllImport("advapi32.dll", CharSet = CharSet.Auto)]
public static extern bool LogonUser(String lpszUserName, String lpszDomain, String lpszPassword, int dwLogonType, int dwLogonProvider, ref IntPtr phToken);
[DllImport("kernel32.dll", CharSet = CharSet.Auto)]
public extern static bool CloseHandle(IntPtr handle);
}
在您的情况下使用它是:
Using it in your case would be:
var domain = ConfigurationManager.AppSettings["reportUserDomain"];
var username = ConfigurationManager.AppSettings["reportUserName"];
var password = ConfigurationManager.AppSettings["reportUserPassword"];
using (Impersonator impersonator = new Impersonator(username, password, domain))
{
var pxs = new ProcessStartInfo
{
Arguments = arguments,
CreateNoWindow = true,
LoadUserProfile = true,
FileName = ConfigurationManager.AppSettings["reportRuntime"],
UseShellExecute = true
};
var px = new Process
{
StartInfo = pxs
};
px.Start();
px.WaitForExit();
}
这篇关于如何在 C# 中启动 32 位进程而不在 64 位机器上使用 shell 执行?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!