带有更改标签的 matplotlib 3d 绘图 [英] matplotlib 3d plot with changing labels
问题描述
所以我有一个 3d 实时更新图！它一次只显示一个点，因此我可以轻松跟踪该点的运动！但问题来了:
So I have a 3d live-updating graph! it only shows one point at a time so I can easily track the motion of the point! But here is the problem:
无论我似乎做什么，点总是放在图形的中心，轴上的刻度线会发生变化，以便做到这一点.这让我的生活变得非常困难，因为我看不到这一点.这是我的代码:
No matter what I seem to do, the point is always placed in the center of the graph and the tick marks on the axis change in order to do that. This makes my life very difficult because I don't see the motion on the point. Here is my code:
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from pylab import *
import time
import pandas as pd
import pickle
def pickleLoad(pickleFile):
pkl_file = open(pickleFile, 'rb')
data = pickle.load(pkl_file)
pkl_file.close()
return data
data = pickleLoad('/Users/ryansaxe/Desktop/kaggle_parkinsons/accelerometry/LILY_dataframe')
data = data.reset_index(drop=True)
df = data.ix[0:,['x.mean','y.mean','z.mean','time']]
ion()
fig = figure()
ax = fig.add_subplot(111, projection='3d')
count = 0
plotting = True
labels = range(-10,11)
ax.set_xlabel('X Label')
ax.set_ylabel('Y Label')
ax.set_zlabel('Z Label')
ax.set_yticklabels(labels)
ax.set_xticklabels(labels)
ax.set_zticklabels(labels)
lin = None
while plotting:
df2 = df.ix[count]
count += 1
xs = df2['x.mean']
ys = df2['y.mean']
zs = df2['z.mean']
t = df2['time']
ax.set_title(t)
if lin is not None:
lin.remove()
lin = ax.scatter(xs, ys, zs)
draw()
pause(0.01)
if count > 100:
plotting = False
ioff()
show()
这是一个数据示例:
x.mean y.mean z.mean time
0 -1.982905 3.395062 8.558263 2012-01-18 14:00:03
1 0.025276 -0.399172 7.404849 2012-01-18 14:00:04
2 -0.156906 -8.875595 1.925565 2012-01-18 14:00:05
3 2.643088 -8.307801 2.382624 2012-01-18 14:00:06
4 3.562265 -7.875230 2.312898 2012-01-18 14:00:07
5 4.441432 -7.907592 2.851774 2012-01-18 14:00:08
6 4.124187 -7.854146 2.727229 2012-01-18 14:00:09
7 4.199698 -8.135596 2.677706 2012-01-18 14:00:10
8 4.407856 -8.133449 2.214902 2012-01-18 14:00:11
9 4.096238 -8.453822 1.359692 2012-01-18 14:00:12
那么我该怎么做才能使刻度线固定，从而使点移动而不是刻度线发生变化?
推荐答案
Axes3D 对象(您的 ax 变量)具有以下方法:set_xlim、set_ylim 和 set_zlim.您可以使用这些来修复轴的限制.
An Axes3D object (your ax variable) has the following methods: set_xlim, set_ylim, and set_zlim. You could use these to fix the limits of your axes.
文档:
编辑
使用 set_xlim 等对我有用.这是我的代码:
Using set_xlim, etc, works for me. Here is my code:
#!python2
from mpl_toolkits.mplot3d import Axes3D
from pylab import *
data = [
[-1.982905, 3.395062, 8.558263, '2012-01-18 14:00:03'],
[ 0.025276, -0.399172, 7.404849, '2012-01-18 14:00:04'],
[-0.156906, -8.875595, 1.925565, '2012-01-18 14:00:05'],
[ 2.643088, -8.307801, 2.382624, '2012-01-18 14:00:06'],
[3.562265, -7.875230, 2.312898, '2012-01-18 14:00:07'],
[4.441432, -7.907592, 2.851774, '2012-01-18 14:00:08'],
[4.124187, -7.854146, 2.727229, '2012-01-18 14:00:09'],
[4.199698, -8.135596, 2.677706, '2012-01-18 14:00:10'],
[4.407856, -8.133449, 2.214902, '2012-01-18 14:00:11'],
[4.096238, -8.453822, 1.359692, '2012-01-18 14:00:12'],
]
ion()
fig = figure()
ax = fig.add_subplot(111, projection='3d')
ax.set_xlabel('X Label')
ax.set_ylabel('Y Label')
ax.set_zlabel('Z Label')
ax.set_xlim((-10, 11))
ax.set_ylim((-10, 11))
ax.set_zlim((-10, 11))
lin = None
for x, y, z, t in data:
ax.set_title(t)
if lin is not None:
lin.remove()
lin = ax.scatter(x, y, z)
draw()
pause(0.1)
ioff()
show()
编辑 2
您可以查看关闭默认情况下启用的轴的自动缩放.也许这会覆盖 set_lim 方法.
You could have a look at switching off autoscaling of axes which is on by default. Maybe this is overriding the set_lim methods.
文档:
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