lambda 表达式中使用的变量应该是最终的或有效的最终 [英] Variable used in lambda expression should be final or effectively final
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问题描述
lambda 表达式中使用的变量应该是 final 或有效 final
Variable used in lambda expression should be final or effectively final
当我尝试使用 calTz
时,它显示此错误.
When I try to use calTz
it is showing this error.
private TimeZone extractCalendarTimeZoneComponent(Calendar cal, TimeZone calTz) {
try {
cal.getComponents().getComponents("VTIMEZONE").forEach(component -> {
VTimeZone v = (VTimeZone) component;
v.getTimeZoneId();
if (calTz == null) {
calTz = TimeZone.getTimeZone(v.getTimeZoneId().getValue());
}
});
} catch (Exception e) {
log.warn("Unable to determine ical timezone", e);
}
return null;
}
推荐答案
final
变量意味着它只能被实例化一次.在 Java 中,您不能在 lambda 以及匿名内部类中重新分配非最终局部变量.
A final
variable means that it can be instantiated only one time.
in Java you can't reassign non-final local variables in lambda as well as in anonymous inner classes.
您可以使用旧的 for-each 循环重构您的代码:
You can refactor your code with the old for-each loop:
private TimeZone extractCalendarTimeZoneComponent(Calendar cal,TimeZone calTz) {
try {
for(Component component : cal.getComponents().getComponents("VTIMEZONE")) {
VTimeZone v = (VTimeZone) component;
v.getTimeZoneId();
if(calTz==null) {
calTz = TimeZone.getTimeZone(v.getTimeZoneId().getValue());
}
}
} catch (Exception e) {
log.warn("Unable to determine ical timezone", e);
}
return null;
}
即使我不明白这段代码的某些部分:
Even if I don't get the sense of some pieces of this code:
- 你调用一个
v.getTimeZoneId();
而不使用它的返回值 - 使用分配
calTz = TimeZone.getTimeZone(v.getTimeZoneId().getValue());
你不会修改最初传递的calTz
并且你不会t 在这个方法中使用它 - 你总是返回
null
,为什么不设置void
作为返回类型?
- you call a
v.getTimeZoneId();
without using its return value - with the assignment
calTz = TimeZone.getTimeZone(v.getTimeZoneId().getValue());
you don't modify the originally passedcalTz
and you don't use it in this method - You always return
null
, why don't you setvoid
as return type?
也希望这些提示能帮助您改进.
Hope also these tips helps you to improve.
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