如何使 2 个整数的除法产生一个浮点数而不是另一个整数? [英] How to make the division of 2 ints produce a float instead of another int?

问题描述

在另一个 Bruce Eckels 计算速度的练习中，v = s/t 其中 s 和 t 是整数.我如何做到这一点，以便该部门产生浮动?

In another Bruce Eckels exercise in calculating velocity, v = s / t where s and t are integers. How do I make it so the division cranks out a float?

class CalcV {
  float v;
  float calcV(int s, int t) {
    v = s / t;
    return v;
  } //end calcV
}

public class PassObject {

  public static void main (String[] args ) {
    int distance;
    distance = 4;

    int t;
    t = 3;

    float outV;

    CalcV v = new CalcV();
    outV = v.calcV(distance, t);

    System.out.println("velocity : " + outV);
  } //end main
}//end class

推荐答案

只需先将两个操作数之一转换为浮点数即可.

Just cast one of the two operands to a float first.

v = (float)s / t;

强制转换的优先级高于除法，因此发生在除法之前.

The cast has higher precedence than the division, so happens before the division.

编译器将有效地自动将另一个操作数强制转换为浮点数，因为规则规定，如果任一操作数是浮点类型，则该操作将是浮点操作，即使另一个操作数是整数也是如此.Java 语言规范，第 4.2 节.4 和 §15.17

The other operand will be effectively automatically cast to a float by the compiler because the rules say that if either operand is of floating point type then the operation will be a floating point operation, even if the other operand is integral. Java Language Specification, §4.2.4 and §15.17

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