json_encode() 非 utf-8 字符串? [英] json_encode() non utf-8 strings?

问题描述

所以我有一个字符串数组，所有字符串都使用系统默认的ANSI 编码并从 SQL 数据库中提取.所以有 256 个不同的可能字符字节值(单字节编码).
有没有办法让 json_encode() 工作并显示这些字符，而不必在我的所有字符串上使用 utf8_encode() 并以 utf8_encode() 结束代码>u0082?

So I have an array of strings, and all of the strings are using the system default ANSI encoding and were pulled from a SQL database. So there are 256 different possible character byte values (single byte encoding).
Is there a way I can get json_encode() to work and display these characters instead of having to use utf8_encode() on all of my strings and ending up with stuff like u0082?

或者这是 JSON 的标准?

Or is that the standard for JSON?

推荐答案

有没有办法让 json_encode() 工作并显示这些字符，而不必在我的所有字符串上使用 utf8_encode() 并以u0082"之类的东西结尾?

Is there a way I can get json_encode() to work and display these characters instead of having to use utf8_encode() on all of my strings and ending up with stuff like "u0082"?

如果你有一个 ANSI 编码的字符串，使用 utf8_encode() 是处理这个问题的错误函数.您需要先将其从 ANSI 正确转换为 UTF-8.这肯定会减少 json 输出中像 u0082 这样的 Unicode 转义序列的数量，但从技术上讲，这些序列 对json有效，你一定不要害怕.

If you have an ANSI encoded string, using utf8_encode() is the wrong function to deal with this. You need to properly convert it from ANSI to UTF-8 first. That will certainly reduce the number of Unicode escape sequences like u0082 from the json output, but technically these sequences are valid for json, you must not fear them.

json_encode 与 UTF-8 编码的字符串仅.如果您需要从 ANSI 编码的字符串成功创建有效的 json，您需要先将其重新编码/转换为 UTF-8.然后 json_encode 将按照文档工作.

json_encode works with UTF-8 encoded strings only. If you need to create valid json successfully from an ANSI encoded string, you need to re-encode/convert it to UTF-8 first. Then json_encode will just work as documented.

从 ANSI 转换编码(更准确地说，我假设您有一个 Windows-1252 编码的字符串，它很流行但被错误地称为 ANSI) 到 UTF-8 你可以使用 mb_convert_encoding() 函数:

To convert an encoding from ANSI (more correctly I assume you have a Windows-1252 encoded string, which is popular but wrongly referred to as ANSI) to UTF-8 you can make use of the mb_convert_encoding() function:

$str = mb_convert_encoding($str, "UTF-8", "Windows-1252");

PHP 中另一个可以转换字符串编码/字符集的函数叫做 iconv 基于 libiconv.您也可以使用它:

Another function in PHP that can convert the encoding / charset of a string is called iconv based on libiconv. You can use it as well:

$str = iconv("CP1252", "UTF-8", $str);

utf8_encode() 的注意事项

utf8_encode() 只做适用于 Latin-1，不适用于 ANSI.因此，当您通过该函数运行该字符串时，您将销毁该字符串中的部分字符.

Note on utf8_encode()

utf8_encode() does only work for Latin-1, not for ANSI. So you will destroy part of your characters inside that string when you run it through that function.

相关:什么是ANSI格式?

要对 json_encode() 返回的内容进行更细粒度的控制，请参阅 预定义常量列表(取决于 PHP 版本，包括 PHP 5.4，一些常量仍未记录在案，目前仅在源代码中可用).

For a more fine-grained control of what json_encode() returns, see the list of predifined constants (PHP version dependent, incl. PHP 5.4, some constants remain undocumented and are available in the source code only so far).

正如您在评论中所写，将函数应用于数组时遇到问题，这里是一些代码示例.在使用 json_encode 之前，总是需要先更改编码.这只是一个标准的数组操作，对于 pdo::fetch() 一个 foreach 迭代的简单情况:

As you wrote in a comment that you have problems to apply the function onto an array, here is some code example. It's always needed to first change the encoding before using json_encode. That's just a standard array operation, for the simpler case of pdo::fetch() a foreach iteration:

while($row = $q->fetch(PDO::FETCH_ASSOC))
{
  foreach($row as &$value)
  {
    $value = mb_convert_encoding($value, "UTF-8", "Windows-1252");
  }
  unset($value); # safety: remove reference
  $items[] = array_map('utf8_encode', $row );
}

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