json_encode（）非utf-8字符串？ [英] json_encode() non utf-8 strings?

问题描述

所以我有一个字符串数组，所有的字符串都使用系统默认的ANSI编码，并从sql数据库中提取。所以有256种不同的可能字符字节值（单字节编码）。有没有办法让json_encode（）工作并显示这些字符，而不必在我的所有字符串上使用utf8_encode（），并以\\\‚这样的东西结束？或者是json的标准吗？

So I have an array of strings, and all of the strings are using the system default ANSI encoding and were pulled from a sql database. So there are 256 different possible character byte values (single byte encoding). Is there a way I can get json_encode() to work and display these characters instead of having to use utf8_encode() on all of my strings and ending up with stuff like "\u0082"?

推荐答案

有没有办法可以让json_encode（）工作并显示这些字符而不是必须在我的所有字符串上使用utf8_encode（），并以\\\‚这样的东西结束？

Is there a way I can get json_encode() to work and display these characters instead of having to use utf8_encode() on all of my strings and ending up with stuff like "\u0082"?

如果你有ANSI编码的字符串，使用 utf8_encode（）是处理此问题的错误函数。您需要首先将其从ANSI转换为UTF-8。这肯定会从json输出中减少Unicode转义序列的数量，如 \\\‚ ，但从技术上讲，这些序列对json有效，你不要害怕。

If you have an ANSI encoded string, using utf8_encode() is the wrong function to deal with this. You need to properly convert it from ANSI to UTF-8 first. That will certainly reduce the number of Unicode escape sequences like \u0082 from the json output, but technically these sequences are valid for json, you must not fear them.

json_encode 与 UTF-8 编码字符串 配合使用。如果您需要从 ANSI 编码字符串中成功创建有效的 json ，则需要重新编码/转换为 UTF-8 然后 json_encode 将正常工作。

json_encode works with UTF-8 encoded strings only. If you need to create valid json successfully from an ANSI encoded string, you need to re-encode/convert it to UTF-8 first. Then json_encode will just work as documented.

要转换 ANSI （更正确地，我假设你有一个 Windows-1252 编码字符串，这是受欢迎但错误地称为$ code> ANSI ）到 UTF-8 可以使用 mb_convert_encoding（） 功能：

To convert an encoding from ANSI (more correctly I assume you have a Windows-1252 encoded string, which is popular but wrongly referred to as ANSI) to UTF-8 you can make use of the mb_convert_encoding() function:

$str = mb_convert_encoding($str, "UTF-8", "Windows-1252");

可以转换字符串的编码/字符集的PHP中的另一个函数称为 iconv 根据 libiconv 。您也可以使用它：

Another function in PHP that can convert the encoding / charset of a string is called iconv based on libiconv. You can use it as well:

$str = iconv("CP1252", "UTF-8", $str);

关于utf8_encode（）的注释

< a href =http://php.net/manual/en/function.utf8-encode.php =nofollow noreferrer> utf8_encode（） 只适用于 Latin-1 ，而不适用于 ANSI 。所以当您通过该函数运行时，您将会损坏字符串中的部分字符。

Note on utf8_encode()

utf8_encode() does only work for Latin-1, not for ANSI. So you will destroy part of your characters inside that string when you run it through that function.

相关：什么是ANSI格式？

对于 json_encode（）返回的更精细的控件，请参阅预定义常量列表（PHP版本依赖，包括PHP 5.4，一些常量保持不记录，仅在源代码中可用

For a more fine-grained control of what json_encode() returns, see the list of predifined constants (PHP version dependent, incl. PHP 5.4, some constants remain undocumented and are available in the source code only so far).

正如您在评论您有将应用程序应用于数组的问题，这里是一些代码示例。在使用 json_encode 之前，首先需要 更改编码。这只是一个标准的数组操作，对于简单的 pdo :: fetch（） a foreach iteration：

As you wrote in a comment that you have problems to apply the function onto an array, here is some code example. It's always needed to first change the encoding before using json_encode. That's just a standard array operation, for the simpler case of pdo::fetch() a foreach iteration:

while($row = $q->fetch(PDO::FETCH_ASSOC))
{
  foreach($row as &$value)
  {
    $value = mb_convert_encoding($value, "UTF-8", "Windows-1252");
  }
  unset($value); # safety: remove reference
  $items[] = array_map('utf8_encode', $row );
}

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