PHP中字符串中的花括号 [英] Curly braces in string in PHP
问题描述
{ }
(花括号)在 PHP 中的字符串字面量是什么意思?
What is the meaning of { }
(curly braces) in string literals in PHP?
推荐答案
这是复杂(卷曲)语法 用于字符串插值.来自手册:
This is the complex (curly) syntax for string interpolation. From the manual:
之所以叫复杂,不是因为语法复杂,而是因为它允许使用复杂的表达式.
Complex (curly) syntax
This isn't called complex because the syntax is complex, but because it allows for the use of complex expressions.
任何带有字符串的标量变量、数组元素或对象属性可以通过此语法包含表示.简单地写表达方式与它出现在字符串外的方式相同,并且然后将其包裹在 {
和 }
中.由于 {
不能转义,所以这个语法仅当 $
紧跟在 {
之后时才会被识别.用{$
获取文字 {$
.一些说明清楚的例子:
Any scalar variable, array element or object property with a string
representation can be included via this syntax. Simply write the
expression the same way as it would appear outside the string, and
then wrap it in {
and }
. Since {
can not be escaped, this syntax
will only be recognised when the $
immediately follows the {
. Use
{$
to get a literal {$
. Some examples to make it clear:
<?php
// Show all errors
error_reporting(E_ALL);
$great = 'fantastic';
// Won't work, outputs: This is { fantastic}
echo "This is { $great}";
// Works, outputs: This is fantastic
echo "This is {$great}";
echo "This is ${great}";
// Works
echo "This square is {$square->width}00 centimeters broad.";
// Works, quoted keys only work using the curly brace syntax
echo "This works: {$arr['key']}";
// Works
echo "This works: {$arr[4][3]}";
// This is wrong for the same reason as $foo[bar] is wrong outside a string.
// In other words, it will still work, but only because PHP first looks for a
// constant named foo; an error of level E_NOTICE (undefined constant) will be
// thrown.
echo "This is wrong: {$arr[foo][3]}";
// Works. When using multi-dimensional arrays, always use braces around arrays
// when inside of strings
echo "This works: {$arr['foo'][3]}";
// Works.
echo "This works: " . $arr['foo'][3];
echo "This works too: {$obj->values[3]->name}";
echo "This is the value of the var named $name: {${$name}}";
echo "This is the value of the var named by the return value of getName(): {${getName()}}";
echo "This is the value of the var named by the return value of $object->getName(): {${$object->getName()}}";
// Won't work, outputs: This is the return value of getName(): {getName()}
echo "This is the return value of getName(): {getName()}";
?>
通常,这种语法是不必要的.例如,这个:
Often, this syntax is unnecessary. For example, this:
$a = 'abcd';
$out = "$a $a"; // "abcd abcd";
行为与此完全相同:
$out = "{$a} {$a}"; // same
所以花括号是不必要的.但是这个:
So the curly braces are unnecessary. But this:
$out = "$aefgh";
将取决于您的错误级别,要么不起作用,要么产生错误,因为没有名为 $aefgh
的变量,所以您需要这样做:
will, depending on your error level, either not work or produce an error because there's no variable named $aefgh
, so you need to do:
$out = "${a}efgh"; // or
$out = "{$a}efgh";
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