如何在 .NET 中生成进程并捕获其 STDOUT? [英] How to spawn a process and capture its STDOUT in .NET?

问题描述

我需要生成一个作为控制台应用程序的子进程，并捕获其输出.

I need to spawn a child process that is a console application, and capture its output.

我为一个方法编写了以下代码:

I wrote up the following code for a method:

string retMessage = String.Empty;
ProcessStartInfo startInfo = new ProcessStartInfo();
Process p = new Process();

startInfo.CreateNoWindow = true;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardInput = true;

startInfo.UseShellExecute = false;
startInfo.Arguments = command;
startInfo.FileName = exec;

p.StartInfo = startInfo;
p.Start();

p.OutputDataReceived += new DataReceivedEventHandler
(
    delegate(object sender, DataReceivedEventArgs e)
    {
        using (StreamReader output = p.StandardOutput)
        {
            retMessage = output.ReadToEnd();
        }
    }
);

p.WaitForExit();

return retMessage;

然而，这不会返回任何东西.我不相信 OutputDataReceived 事件正在被回调，或者 WaitForExit() 命令可能会阻塞线程，因此它永远不会回调.

However, this does not return anything. I don't believe the OutputDataReceived event is being called back, or the WaitForExit() command may be blocking the thread so it will never callback.

有什么建议吗?

看起来我对回调太用力了.做:

Looks like I was trying too hard with the callback. Doing:

return p.StandardOutput.ReadToEnd(); 

看起来工作正常.

推荐答案

这是我已经验证可以工作的代码.我用它来生成 MSBuild 并监听它的输出:

Here's code that I've verified to work. I use it for spawning MSBuild and listening to its output:

process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.OutputDataReceived += (sender, args) => Console.WriteLine("received output: {0}", args.Data);
process.Start();
process.BeginOutputReadLine();

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