在 Ruby 中生成后台进程 [英] Spawn a background process in Ruby

问题描述

我正在为一个学校项目编写一个 ruby​​ 引导脚本，这个引导过程的一部分是启动几个后台进程(它们被编写并正常运行).我想做的是类似的事情:

`/path/to/daemon1 &``/path/to/daemon2 &``/path/to/daemon3 &`

然而，这会在第一次调用执行 daemon1 时阻塞.我见过对 Process.spawn 方法的引用，但这似乎是 1.9+ 的特性，而且我仅限于 Ruby 1.8.

我也尝试从不同的线程执行这些守护进程，但我希望我的引导脚本能够退出.

那么我该如何启动这些后台进程，以便我的引导脚本不会被阻塞并且可以退出(但仍然让守护进程在后台运行)?

解决方案

只要你在 POSIX 操作系统上工作，你就可以使用 fork 和 exec.

fork = 创建子进程

exec = 用另一个进程替换当前进程

然后您需要通过 Process.detach 通知您的主进程对创建的子进程不感兴趣.

job1 = fork do执行/path/to/daemon01"结尾Process.detach(job1)...

I'm writing a ruby bootstrapping script for a school project, and part of this bootstrapping process is to start a couple of background processes (which are written and function properly). What I'd like to do is something along the lines of:

`/path/to/daemon1 &`
`/path/to/daemon2 &`
`/path/to/daemon3 &`

However, that blocks on the first call to execute daemon1. I've seen references to a Process.spawn method, but that seems to be a 1.9+ feature, and I'm limited to Ruby 1.8.

I've also tried to execute these daemons from different threads, but I'd like my bootstrap script to be able to exit.

So how can I start these background processes so that my bootstrap script doesn't block and can exit (but still have the daemons running in the background)?

解决方案

As long as you are working on a POSIX OS you can use fork and exec.

fork = Create a subprocess

exec = Replace current process with another process

You then need to inform that your main-process is not interested in the created subprocesses via Process.detach.

job1 = fork do
  exec "/path/to/daemon01"
end

Process.detach(job1)

...

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