GroupBy 结果到列表字典 [英] GroupBy results to dictionary of lists

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本文介绍了GroupBy 结果到列表字典的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个看起来像这样的 Excel 表格:

I have an excel sheet that looks like so:

Column1 Column2 Column3
0       23      1
1       5       2
1       2       3
1       19      5
2       56      1
2       22      2
3       2       4
3       14      5
4       59      1
5       44      1
5       1       2
5       87      3

我希望提取该数据,按第 1 列对其进行分组,然后将其添加到字典中,使其显示如下:

And I'm looking to extract that data, group it by column 1, and add it to a dictionary so it appears like this:

{0: [1],
1: [2,3,5],
2: [1,2],
3: [4,5],
4: [1],
5: [1,2,3]}

这是我目前的代码

excel = pandas.read_excel(r"e:	est_data.xlsx", sheetname='mySheet', parse_cols'A,C')
myTable = excel.groupby("Column1").groups
print myTable

但是,我的输出如下所示:

However, my output looks like this:

{0: [0L], 1: [1L, 2L, 3L], 2: [4L, 5L], 3: [6L, 7L], 4: [8L], 5: [9L, 10L, 11L]}

谢谢!

推荐答案

You can groupby on Column1 然后将 Column3 带到 >apply(list) 并调用 to_dict?

You could groupby on Column1 and then take Column3 to apply(list) and call to_dict?

In [81]: df.groupby('Column1')['Column3'].apply(list).to_dict()
Out[81]: {0: [1], 1: [2, 3, 5], 2: [1, 2], 3: [4, 5], 4: [1], 5: [1, 2, 3]}

或者,做

In [433]: {k: list(v) for k, v in df.groupby('Column1')['Column3']}
Out[433]: {0: [1], 1: [2, 3, 5], 2: [1, 2], 3: [4, 5], 4: [1], 5: [1, 2, 3]}

这篇关于GroupBy 结果到列表字典的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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