如何更新列表字典中的值 [英] how to update values in dictionary of lists

问题描述

我正在尝试更新列表字典
中的值EX：我有字典输入：

I'm trying to update values in dictionary of lists EX: I have a dictionary input:

d={0: [0,1], 1:[1],2:[2],3:[3]}

和 [0,2]
对，我想将dict中的每个0替换为0.2，并增加每个值> 2比1，因此这里的预期输出是：

and pair [0,2] and I want to replace every 0 in dict with 0,2 and increase each value >2 by 1, so here the expected output:

{0: [0,2,1], 1:[1],2:[2],3:[4]}

我尝试遍历所有值，但这并不能正确地解决问题。

I tried to iterate over all values, but it didn't make the trick properly

def update_dict(_dict,_pair):
    for i in range(len(_dict.keys())):
        for j in range(len(_dict.values()[i])):
            if dict[i][j]==_pair[0]:
                dict[i][j].remove(_pair[0])
                dict[i].append(_pair)
    return _dict

如何实现？
预先感谢您的帮助

How do I achieve that? Thanks in advance for any help

推荐答案

您在这里不需要词典，您需要列表；您有一个从0开始的有序键序列，列表的索引将更有效地满足需要：

You don't need a dictionary here, you want a list; you have an ordered series of keys starting at 0, indices of a list would more efficiently serve that need:

l = [[0,1], [1], [2], [3]]

您可以生成期望的输出：

You can produce the desired output:

for i, nested in enumerate(l):
    # replace all 0 values with 1, 2
    while 0 in nested:
        zero_index = nested.index(0)
        nested[zero_index:zero_index + 1] = [1, 2]
    # increment values in the nested list if the index is over 2:
    if i > 2:
        nested[:] = [v + 1 for v in nested]

此在原位置更改原始嵌套列表。

This alters the original nested lists in-place.

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