如何访问 JSON 对象名称/值? [英] How to access JSON Object name/value?

问题描述

function (data) {
    //add values based on activity type
    //data = JSON.parse(data);
    //alert(abc.Phone1);

    alert(data.myName)

    alert(data.toString());
    if (activityType == "Phone") {
    }
    return;

},

如你所见，$.ajax 的回调函数从控制器中获取 JSON 数据.

As you can see this callback function of $.ajax taking JSON data from controller.

例如:

[{"name":"myName","address":"myAddress" }]

在这种情况下，我的第一个警报给我未定义和第二/第三个警报弹出窗口:

In this case my first alert giving me undefined and second/third alert popup comes up with:

[{"name":"myName" ,"address": "myAddress" }]

如何按名称访问值，以便我的第一个警报用 myName 填充，这是 name 的值?

How can I access value by name so that my first alert filled out with myName which is value of name?

推荐答案

除了解析 JSON，您还可以执行以下操作:

In stead of parsing JSON you can do like followng:

$.ajax({
  ..
  dataType: 'json' // using json, jquery will make parse for  you
});

要访问 JSON 的属性，请执行以下操作:

To access a property of your JSON do following:

data[0].name;

data[0].address;

---

为什么你需要 data[0] 因为数据是一个数组，所以要检索它的内容，你需要 data[0](第一个元素)，它给你一个object {name":myName";，地址":我的地址"}.

---

Why you need data[0] because data is an array, so to its content retrieve you need data[0] (first element), which gives you an object {"name":"myName" ,"address": "myAddress" }.

访问对象属性的规则是:

And to access property of an object rule is:

Object.property

有时

Object["property"] // in some case

所以你需要

data[0].name 等得到你想要的.

set dataType: json 然后你需要使用 $.parseJSON() 解析它们并像上面一样检索数据.

set dataType: json then you need to parse them using $.parseJSON() and to retrieve data like above.

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