MVC4：包括以JSON对象名称 [英] MVC4: Include object name in Json

问题描述

我有我一直在挣扎了一段时间MVC4（测试版）问题的问题。问题是，我想创建增加了我的WebAPI对象名称的JSON。将JSON必须创建，这是作为接收端需要这一点。我的.NET / MVC的知识有限，所以请多多包涵。我想关于这个问题的搜索，但MVC4仍处于测试阶段，很难找到关于这一问题的好消息。

I have a question on a MVC4 (beta) issue I have been struggling with for some time now. The issue is that I want to create a json with the object name added for my webapi. The json has to be created this was as the receiving side needs this. My .NET/MVC knowledge is limited so please bear with me. I tried searching on the subject, but as MVC4 is still in beta it's difficult to find good info on this subject.

我已经导入我的解决方案的JSON.NET格式化，但是这不会添加对象名称

I have already imported the JSON.NET formatter in my solution, but this does not add the Object name

这是目前在MVC4创建JSON：

The json that is now created in MVC4:

[{"ID":36,"Name":"Test3","Description":"Description Test3"},{"ID": 37,"Name": "Test4","Description": "Description Test4"}]

和我想的JSON看起来是这样的：

And I would like the json to look like this:

{"Goal":[{"ID":36,"Name":"Test3","Description":"Description Test3"},{"ID": 37,"Name": "Test4","Description": "Description Test4"}]}

所以我喜欢的对象名称（目标），以包含在JSON。

So I like the object name (Goal) to be included in the json.

在我的API控制器中的code我使用的是这样的：

The code in my api controller I am using for this is:

    StoreDBContext db = new StoreDBContext();

    //
    // GET /api/goals
    public IQueryable<Goals> Get()
    {
        return db.Goals;
    }

我想我需要遍历某处添加对象的名字，但我不知道如何...希望有人能帮助我这个！

I assume I need to loop through somewhere to add the object name, but I am not sure how... Hopefully someone can help me out with this!

推荐答案

返回是这样的：

new { Goal = db.Goals().AsEnumerable().ToList() }

您可以使用一个匿名对象添加不在对象属性和东西。

You can use an anonymous object to add properties and stuff that aren't in the object.

您也可以编写自定义转换器JSON.NET如果你想让它正确地反序列化，但如果你不关心输出的反序列化，上面的解决方案，将工作。

You can also write custom converters for JSON.NET if you want it to deserialize properly, but if you don't care about deserialization of the output, the above solution will work.

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