如何在不使用 try/except 的情况下检查字符串是否代表 int? [英] How can I check if a string represents an int, without using try/except?

问题描述

有什么办法可以判断一个字符串是否代表一个整数(例如，'3'、'-17'但不是'3.14' 或 'asfasfas') 不使用 try/except 机制?

Is there any way to tell whether a string represents an integer (e.g., '3', '-17' but not '3.14' or 'asfasfas') Without using a try/except mechanism?

is_int('3.14') == False
is_int('-7')   == True

推荐答案

如果您真的只是对到处使用 try/except 感到恼火，请编写一个辅助函数:

If you're really just annoyed at using try/excepts all over the place, please just write a helper function:

def RepresentsInt(s):
    try: 
        int(s)
        return True
    except ValueError:
        return False

>>> print RepresentsInt("+123")
True
>>> print RepresentsInt("10.0")
False

要准确覆盖 Python 认为是整数的所有字符串，将需要更多代码.我说只是在这个上pythonic.

It's going to be WAY more code to exactly cover all the strings that Python considers integers. I say just be pythonic on this one.

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