有没有更好的方法来迭代两个列表，每次迭代从每个列表中获取一个元素? [英] Is there a better way to iterate over two lists, getting one element from each list for each iteration?

问题描述

我有一个纬度列表和一个经度列表，需要遍历纬度和经度对.

I have a list of Latitudes and one of Longitudes and need to iterate over the latitude and longitude pairs.

是否更好:

• A.假设列表长度相等:

• A. Assume that the lists are of equal lengths:

for i in range(len(Latitudes)):
    Lat,Long=(Latitudes[i],Longitudes[i])

B.或者:

B. Or:

for Lat,Long in [(x,y) for x in Latitudes for y in Longitudes]:

(注意 B 不正确.这给了我所有的对，相当于 itertools.product())

(Note that B is incorrect. This gives me all the pairs, equivalent to itertools.product())

对每个的相对优点有什么想法，或者哪个更pythonic?

Any thoughts on the relative merits of each, or which is more pythonic?

推荐答案

这就像你能得到的那样 Pythonic:

This is as pythonic as you can get:

for lat, long in zip(Latitudes, Longitudes):
    print(lat, long)

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