如何确定“调试模式"是否存在已启用 [英] How to find out if "debug mode" is enabled

问题描述

Java 程序如何知道它是否在调试模式下运行?

How can a Java program find out if it is running in debug mode?

应用程序在常规全速"模式下的行为应与调试模式"(当连接调试器时，在调试模式下运行时)略有不同.应用程序通过 TCP 与另一台计算机、另一个进程或自身内部进行通信.我的同事希望我们默认使用 Socket.setSoTimeout(1000)，这样从套接字读取最多可以阻塞 1 秒.在调试时，这当然是不够的，应用程序将停止正常工作.因此，解决方案是将 SO_TIMEOUT 设置得更高，但只是在调试模式下(例如:无限制).现在，我并不总是设置断点，或者不想使用可以自己设置调试"属性的调试版本.有时我会附加调试器(远程调试).我主要使用 Eclipse，所以一个在那里工作的解决方案是可以的.

The application should behave a bit different in regular "full speed" mode than in "debug mode" (when a debugger is attached, when running in debug mode). The application communicates over TCP with either another computer, another process, or within itself. My co-worker wants us to use Socket.setSoTimeout(1000) by default, so that reads from the socket can block for at most 1 second. When debugging, this is not enough of course, and the application stops working as it should. So a solution would be to set the SO_TIMEOUT higher, but just in debug mode (for example: unlimited). Now, I don't always set breakpoints or don't want use a debug build where I could set the "debug" property myself. Sometimes I attach the debugger (remote debugging). I'm mainly using Eclipse so a solution that just works there is OK.

可能的答案包括:

1. 要查看是否在调试模式下运行，请在 java.lang.management.* 或 javax.management.* 中使用以下方法...

1. To find out if run in debug mode, use the following method in java.lang.management.* or javax.management.* ...

由于 X 原因，您的同事错了，您不应将 SO_TIMEOUT 默认设置为 1 秒.

Your co-worker is wrong for reason X, you shouldn't set SO_TIMEOUT to 1 second by default.

更新

我了解系统属性方法，但我将问题悬而未决以解决我最初的问题.

Update

I know about the system property approach, but I leave the question open to solve my original question.

推荐答案

我现在自己发现了:

boolean isDebug = java.lang.management.ManagementFactory.getRuntimeMXBean().
    getInputArguments().toString().indexOf("jdwp") >= 0;

这将检查 Java Debug Wire使用协议代理.

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