无法在Flask中启用调试模式 [英] Can't enable debug mode in Flask
问题描述
from flask import Flask
from config import config
$ b def create_app(config_name):
app = Flask(__ name__)
app.config.from_object(config [config_name])
config [ config_name] .init_app(app)
$ b $ from .main import main main as main_blueprint
app.register_blueprint(main_blueprint)
from .api import api as api_blueprint
app.register_blueprint(api_blueprint,url_prefix ='/ api / v1.0')
返回应用程序
这里是我的config.py:
$ p $ import os
basedir = os.path.abspath(os.path.dirname(__ file__))
类配置:
SECRET_KEY ='12345'
SQL_DRIVER ='SQL Server Native Client 11.0'
SQL_SERVER ='WIN8 \MSSQL2K12'
SQL_DATABASE ='LogMe'
SQL_USER ='LogMe'
SQL_PASSWORD ='密码'
@staticmethod
def init_app(app):
pass
$ b $ class DevelopmentConfig(Config):
DEBUG = True
config = {
'development':DevelopmentConfig
}
整个项目在GitHub上,如果碰巧是其他地方的问题,但我认为它在这两个文件中的某个地方:
https://github.com/jcaine04/perf-dash/tree/master/app
app.run()
服务器。如果您使用不同的WSGI服务器,则需要明确添加调试器中间件: def create_app(config_name):
app = Flask(__ name__)
#...
if app.debug:
from werkzeug.debug import DebuggedApplication
app.wsgi_app = DebuggedApplication (app.wsgi_app,True)
返回应用程序
当您使用<一个href =http://flask-script.readthedocs.org/en/latest/ =nofollow> Flask-Script , runserver
运行Flask WSGI开发服务器,并启用调试器。
不幸的是,Flask-Script 2.0.3版引入了一个bug ;它不会正确设置新的调试标志,除非明确地传递 -d
标志,否则总是禁用调试器。这是不管你设置 use_debugger
为true;这是因为 argparse
store_true
选项的默认值是存储 False
$ b
解决方法是明确地使用 -d
,或调试 flask_script / commands.py 给所有 - debug
和 --no-debug
选项 self.use_debugger
作为默认值:
if self.use_debugger:
options + =(Option(' - d','--debug',
action ='store_true',
dest =' use_debugger',
help =(no-op for compatibility),
default = self.use_debugger),
options + =(Option(' - D','--no '
action ='store_false',
dest ='use_debugger',
default = self.use_debugger),
:
options + =(Option(' - d','--debug ',
action ='store_true',
dest ='use_debugger',
default = self.use_debugger),
options + =(Option(' - D',' --no-debug',
action ='store_false',$ b $ dest ='use_debugger',
help =(不兼容),
default = self .use_debugger))
其中我添加了 处理 版本0.6.7和1.0不会受到这个bug的影响;一个修复已经提交了2.0.4版本(还没有发布)。 I have a fairly basic Flask app, but for some reason Debug mode wont enable, so whenever I get an error I get a 500 page instead of the nice debug page with the traceback and all that. Here's my app/init.py: and here's my config.py: I've posted the whole project up on GitHub if there happens to be an issue elsewhere, but I assume it's somewhere in these two files:
https://github.com/jcaine04/perf-dash/tree/master/app The debugger is part of the WSGI runner; the When you use Flask-Script, the Unfortunately, Flask-Script version 2.0.3 introduced a bug; it doesn't set up the new debug flags correctly and always disabled the debugger unless you explicitly pass in the The work-around is to explicitly use where I've added The handling of Versions 0.6.7 and 1.0 don't suffer from this bug; a fix has been committed for version 2.0.4 (not as yet released). 这篇关于无法在Flask中启用调试模式的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋! default = self.use_debugger $ b
self.use_reloader $ c
这两个选项还没有设置。 $ c>也有类似的缺陷。
from flask import Flask
from config import config
def create_app(config_name):
app = Flask(__name__)
app.config.from_object(config[config_name])
config[config_name].init_app(app)
from .main import main as main_blueprint
app.register_blueprint(main_blueprint)
from .api import api as api_blueprint
app.register_blueprint(api_blueprint, url_prefix='/api/v1.0')
return app
import os
basedir = os.path.abspath(os.path.dirname(__file__))
class Config:
SECRET_KEY = '12345'
SQL_DRIVER = 'SQL Server Native Client 11.0'
SQL_SERVER = 'WIN8\MSSQL2K12'
SQL_DATABASE = 'LogMe'
SQL_USER = 'LogMe'
SQL_PASSWORD = 'password'
@staticmethod
def init_app(app):
pass
class DevelopmentConfig(Config):
DEBUG = True
config = {
'development' : DevelopmentConfig
}
app.run()
server. If you use a different WSGI server you need to explicitly add the debugger middleware:def create_app(config_name):
app = Flask(__name__)
# ...
if app.debug:
from werkzeug.debug import DebuggedApplication
app.wsgi_app = DebuggedApplication(app.wsgi_app, True)
return app
runserver
runs the Flask WSGI development server and will enable the debugger.-d
flag. This is regardless of wether you set use_debugger
to true; this because the default of an argparse
store_true
option is to store False
instead when not picked.-d
, or to patch flask_script/commands.py
to give all --debug
and --no-debug
options self.use_debugger
as the default:if self.use_debugger:
options += (Option('-d', '--debug',
action='store_true',
dest='use_debugger',
help="(no-op for compatibility)",
default=self.use_debugger),)
options += (Option('-D', '--no-debug',
action='store_false',
dest='use_debugger',
default=self.use_debugger),)
else:
options += (Option('-d', '--debug',
action='store_true',
dest='use_debugger',
default=self.use_debugger),)
options += (Option('-D', '--no-debug',
action='store_false',
dest='use_debugger',
help="(no-op for compatibility)",
default=self.use_debugger),)
default=self.use_debugger
to the two options that did not yet have it set.self.use_reloader
is similarly flawed.