提交搜索表单后，无法使用 Flask 应用程序从 url 检索变量 [英] Can't retrieve variable from url with Flask app after submitting search form

问题描述

我想在用户提交搜索表单后呈现一个新视图.我以与其他视图相同的方式制作它，但不幸的是这次没有发生任何事情，我无法从应用程序路由中检索内容.(所以这个问题不是 this 问题，该问题仅在提交表单后出现，它在其他所有情况下都能完美运行.)我在表单中写入一些内容，提交它，然后浏览器中的 url 更改，但无论如何视图都没有更改.我几乎可以肯定这是因为搜索 slug 中的 ? 和 = ，但不知道我应该如何在 Python 代码中处理它们.

实际上，当我提交表单时，我的浏览器会将我重定向到这样的网址:

http://domain/.com/?search=content+from+textfield

这就是我尝试从搜索字段中获取内容并在 Flask 一侧呈现新视图的方式:

@app.route('/?search=', methods=['POST'])def hello_url(url_content):return render_template("search-results.html", searchString = url_content])

如果有人能告诉我正确的方式，我真的很感激，基本上我只想在搜索按钮后检索 <url_content> 在 hello_url 函数中的值敲击.

这是我的 html:

<div class="form-group"><input type="search" class="form-control text-center input-lg" id="inputSearch" name="search" placeholder="search">

<br><div class="text-center"><button type="submit" class="btn btn-primary btn-lg">搜索！</button></div></表单>

解决方案

你混淆了使用 捕获的 url 参数和 中访问的查询参数>request.args.从路由定义中删除查询参数并在视图中访问它.

来自烧瓶导入请求@app.route('/')定义索引():返回 render_template('index.html')@app.route('/搜索')定义搜索():search = request.args.get('search') # 如果没有提交表单，则为 None# 用搜索做一些事情return render_template('search.html', search=search)

index.html:

<输入名称=搜索"/><input type="submit" value="搜索"/></表单>

I would like to present a new view after the user submits a search form. I made it as the same way as I do with my other views, but unfortunately this time doesn't happens anything, I can't retrieve the content from the app route. (So this question is not a duplicate of this question, the issue occurs only after submitting the form, it works perfectly in every other situation.) I write something into the form, submit it, then the url changes in the browser, but the view doesn't change anyway. I'm almost sure that it's because the ? and = in the search slug, but don't know how should I deal with them in the Python code.

Actually when I submit the form my browser redirects me to an url like this:

http://domain/.com/?search=content+from+textfield

And this is how I tried to catch the content from the search field and present a new view on the Flask's side:

@app.route('/?search=<url_content>', methods=['POST'])
def hello_url(url_content): 
return render_template("search-results.html", searchString = url_content])

I would really appreciate if somebody could show me the right way, basically I just wanna retrieve the value of <url_content> inside the hello_url function after the search button tapped.

Here's my html:

<form>
 <div class="form-group">
    <input type="search" class="form-control text-center input-lg" id="inputSearch" name="search" placeholder="search">
    </div>
     <br>
<div class="text-center"><button type="submit" class="btn btn-primary btn-lg">Search!</button></div>
</form>

解决方案

You're confusing url parameters, which are captured with <variable>, with query parameters, which are accessed in request.args. Remove the query parameter from your route definition and access it in the view.

from flask import request

@app.route('/')
def index():
    return render_template('index.html')

@app.route('/search')
def search():
    search = request.args.get('search')  # will be None if form wasn't submitted
    # do something with search
    return render_template('search.html', search=search)

index.html:

<form action="{{ url_for('search') }}">
    <input name="search"/>
    <input type="submit" value="Search"/>
</form>

这篇关于提交搜索表单后，无法使用 Flask 应用程序从 url 检索变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！