如何在 Scala 中使用 vararg 和不使用 vararg 的方法之间消除歧义 [英] How do I disambiguate in Scala between methods with vararg and without

问题描述

我正在尝试使用 Scala 的 java jcommander 库.java JCommander 类有多个构造函数:

I'm trying to use the java jcommander library from Scala. The java JCommander class has multiple constructors:

 public JCommander(Object object)  
 public JCommander(Object object, ResourceBundle bundle, String... args)   
 public JCommander(Object object, String... args)   

我想调用第一个采用无可变参数的构造函数.我试过了:

I want to to call the first constructor that takes no varargs. I tried:

jCommander = new JCommander(cmdLineArgs)

我收到错误:

error: ambiguous reference to overloaded definition,
both constructor JCommander in class JCommander of type (x$1: Any,x$2: <repeated...>[java.lang.String])com.beust.jcommander.JCommander
and  constructor JCommander in class JCommander of type (x$1: Any)com.beust.jcommander.JCommander
match argument types (com.lasic.CommandLineArgs) and expected result type com.beust.jcommander.JCommander
jCommander = new JCommander(cmdLineArgs)

我也尝试过使用命名参数，但得到了相同的结果:

I've also tried using a named parameter, but got the same result:

jCommander = new JCommander(`object` = cmdLineArgs)

我如何告诉 Scala 我想调用不带可变参数的构造函数?

How do I tell Scala I want to call the constructor that doesn't take varargs?

我使用的是 Scala 2.8.0.

I'm using Scala 2.8.0.

推荐答案

抱歉，我现在意识到这是一个已知的 Java 互操作性问题.请参阅这个问题和票.我所知道的唯一解决方法是创建一个小的 Java 类来消除这些调用的歧义.

Sorry, I now realize this is a known interoperability problem with Java. See this question and the ticket. The only work around I know of is to create a small Java class just to disambiguate these calls.

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