Python:鉴于原始电子邮件没有“正文"，如何从原始电子邮件解析正文标签或任何东西 [英] Python : How to parse the Body from a raw email , given that raw email does not have a "Body" tag or anything

问题描述

看起来很容易获得

From
To
Subject

等通过

import email
b = email.message_from_string(a)
bbb = b['from']
ccc = b['to']

假设 "a" 是看起来像这样的原始电子邮件字符串.

assuming that "a" is the raw-email string which looks something like this.

a = """From [e-mail] Thu Jul 25 19:28:59 2013
Received: from a1.local.tld (localhost [127.0.0.1])
    by a1.local.tld (8.14.4/8.14.4) with ESMTP id r6Q2SxeQ003866
    for <[e-mail]>; Thu, 25 Jul 2013 19:28:59 -0700
Received: (from root@localhost)
    by a1.local.tld (8.14.4/8.14.4/Submit) id r6Q2Sxbh003865;
    Thu, 25 Jul 2013 19:28:59 -0700
From: [e-mail]
Subject: oooooooooooooooo
To: [e-mail]
Cc: 
X-Originating-IP: 192.168.15.127
X-Mailer: Webmin 1.420
Message-Id: <1374805739.3861@a1>
Date: Thu, 25 Jul 2013 19:28:59 -0700 (PDT)
MIME-Version: 1.0
Content-Type: multipart/mixed; boundary="bound1374805739"

This is a multi-part message in MIME format.

--bound1374805739
Content-Type: text/plain
Content-Transfer-Encoding: 7bit

ooooooooooooooooooooooooooooooooooooooooooooooo
ooooooooooooooooooooooooooooooooooooooooooooooo
ooooooooooooooooooooooooooooooooooooooooooooooo

--bound1374805739--"""

问题

你如何通过python获取这封电子邮件的Body?

how do you get the Body of this email via python ?

到目前为止，这是我知道的唯一代码，但我还没有对其进行测试.

So far this is the only code i am aware of but i have yet to test it.

if email.is_multipart():
    for part in email.get_payload():
        print part.get_payload()
else:
    print email.get_payload()

这是正确的方法吗?

或者也许有一些更简单的东西，比如...

or maybe there is something simpler such as...

import email
b = email.message_from_string(a)
bbb = b['body']

?

推荐答案

使用 Message.get_payload

b = email.message_from_string(a)
if b.is_multipart():
    for payload in b.get_payload():
        # if payload.is_multipart(): ...
        print payload.get_payload()
else:
    print b.get_payload()

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