Python imaplib 获取正文电子邮件 gmail [英] Python imaplib fetch body emails gmail

问题描述

我已阅读此内容 并编写此脚本以获取某个邮箱中标题以$"开头并由某个发件人发送的电子邮件正文.

I read this already and wrote this script to fetch body for emails in some mail box which title begins with '$' and is sent by some sender.

import email, getpass, imaplib, os

detach_dir = "F:PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")

# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)

m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes

resp, items = m.search(None, '(FROM "[e-mail]")')
items = items[0].split() # getting the mails id

my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
    resp, data = m.fetch(emailid, "(RFC822)")
    if ( break_ ):
        break 
    for response_part in data:
      if isinstance(response_part, tuple):
          msg = email.message_from_string(response_part[1])
          varSubject = msg['subject']
          if varSubject[0] == '$':
              msg_cnt += 1
              my_msg.append(msg)
              print msg_cnt
              print email.message_from_string(response_part[1])
              if ( msg_cnt == 5 ):
                  break_ = True 

如果我打印 email.message_from_string(response_part[1])，我可以看到它包含第一个信息(标题、发件人、收件人、日期...)，全文正文.但是，我无法取回尸体本身.email.message_from_string(response_part[0]) 打印邮件 IDS，email.message_from_string(response_part[2]) 超出范围.email.message_from_string(response_part[1][0]) 两者都没有.

if I print email.message_from_string(response_part[1]), I can see it contains first information (header, from, to, date...), the the full text body. But, I cannot fetch the body itself. email.message_from_string(response_part[0]) prints mails IDS, and email.message_from_string(response_part[2]) is out of range. email.message_from_string(response_part[1][0]) neither is doing it.

谢谢和问候.

更新

现在，我几乎可以拥有正文了.然而，它仍然被首先出现的信息声明破坏了.结果我得到了

Now, I can almost have body text. However, it is still spoilt by an information statement coming first. I get as a result

From nobody Tue Dec 25 11:42:58 2012

US=3D$4.030

EastCst=3D$4.036

NewEng=3D$4.205

CenAtl=3D$4.149

LwrAtl=3D$3.921

Midwst=3D$3.984

GulfCst=3D$3.945

RkyMt=3D$4.195

WCst=3D$4.187

CA=3D$4.268

我想摆脱 From nobody Tue Dec 25 11:42:58 2012 这是信息.我知道我可以解析文本查找第一个相关行...我知道.

and I would like to get rid of From nobody Tue Dec 25 11:42:58 2012 which is information. I know I could parse text look for first relevant line... i know.

实现这一点的代码(插入我的第一个示例)是

The code for achieving so (to plug in my first sample) is

  if varSubject[0] == '$':
      r, d = m.fetch(emailid, "(UID BODY[TEXT])")
      msg_cnt += 1
      my_msg.append(msg)
      print email.message_from_string(d[0][1])

你有更好的方法吗(没有信息字符串)???更多:现在获取日期的命令是什么?我知道我可以在上面适合的地方做 varDate = msg['date'] ，但是如何只获取 day-month-year ?谢谢

Do you have a better way (no info string) ??? More: what is the command to now fetch the date ? I know that I can do varDate = msg['date'] where suited above, but how to just fetch day-month-year ? THANKS

推荐答案

可以通过以下任一方式获取 body 的内容

You can get the contents of the body by doing any of the following

msg.as_string()
str(msg)
repr(msg)

http://docs.python.org/2.7/library/email.message.html#email.message.Message

这篇关于Python imaplib 获取正文电子邮件 gmail的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！