Python imaplib抓取电子邮件gmail [英] Python imaplib fetch body emails gmail

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问题描述

/ a>,并写了这个脚本来获取电子邮件的一些邮箱的电子邮件标题以'$'开头,由某些发件人发送。

  import email,getpass,imaplib,os 

detach_dir =F:\PYTHONPROJECTS#将保存附件的
user = raw_input(输入您的GMail用户名 - >)
pwd = getpass.getpass(输入您的密码 - >)

#连接到gmail imap服务器
m = imaplib.IMAP4_SSL(imap .gmail.com)
m.login(user,pwd)

m.select(PETROLEUM)#这里你可以选择一个像INBOX这样的邮箱,而不是
#使用m.list()获取所有邮箱

resp,items = m.search(无,'(FROMEIA_eLists@eia.gov)')
items = items [0] .split()#获取邮件id

my_msg = []#存储相关msgs在这里请
msg_cnt = 0
break_ = False
项目[:: - 1]中的emailid:
resp,data = m.fetch(emailid,(RFC822))
if(break_):
break
for response_part in data:
if isinstance(response_part,tuple):
msg = email.message_from_string(response_part [1])$ ​​b $ b varSubject = msg ['subject']
如果varSubject [0] =='$':
msg_cnt + = 1
my_msg.append(msg)
打印msg_cnt
打印email.message_from_string(response_part [1])
if(msg_cnt == 5):
break_ = True

如果我打印 email.message_from_string(response_part [1]),我可以看到它包含第一个信息(标题,从,到,日期...),全文本体。但是,我不能抓住身体本身。 email.message_from_string(response_part [0])打印邮件IDS和 email.message_from_string(response_part [2])超出范围。 email.message_from_string(response_part [1] [0])既没有这样做。



谢谢, / p>

更新



现在,我几乎可以拥有正文。然而,它仍然受到首先发布的信息声明的破坏。我得到一个结果

 从nobody Tue Dec 25 11:42:58 2012 

US = 3D $ 4.030

EastCst = 3D $ 4.036

NewEng = 3D $ 4.205

CenAtl = 3D $ 4.149

LwrAtl = 3D $ 3.921

Midwst = 3D $ 3.984

GulfCst = 3D $ 3.945

RkyMt = 3D $ 4.195

WCst = 3D $ 4.187

CA = 3D $ 4.268

我想摆脱从nobody Tue Dec 25 11:42:58 2012 哪个是信息。我知道我可以解析第一个相关行的文本寻找...我知道。



实现这个(插入我的第一个样本)的代码是

 如果varSubject [0] =='$':
r,d = m.fetch(emailid,(UID BODY [TEXT ])
msg_cnt + = 1
my_msg.append(msg)
print email.message_from_string(d [0] [1])$ ​​b $ b
你有一个更好的方法(没有信息字符串)?/ pre>

更多:现在获取日期的命令是什么?我知道我可以在上面适用的 varDate = msg ['date'] ,但是如何只获取日月 - 年?感谢

解决方案

您可以通过执行以下任何一项获取身体的内容:

  msg.as_string()
str(msg)
repr(msg)

http://docs.python.org/2.7/library/email.message.html#email.message.Message


I read this already and wrote this script to fetch body for emails in some mail box which title begins with '$' and is sent by some sender.

import email, getpass, imaplib, os

detach_dir = "F:\PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")

# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)

m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes

resp, items = m.search(None, '(FROM "EIA_eLists@eia.gov")')
items = items[0].split() # getting the mails id

my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
    resp, data = m.fetch(emailid, "(RFC822)")
    if ( break_ ):
        break 
    for response_part in data:
      if isinstance(response_part, tuple):
          msg = email.message_from_string(response_part[1])
          varSubject = msg['subject']
          if varSubject[0] == '$':
              msg_cnt += 1
              my_msg.append(msg)
              print msg_cnt
              print email.message_from_string(response_part[1])
              if ( msg_cnt == 5 ):
                  break_ = True 

if I print email.message_from_string(response_part[1]), I can see it contains first information (header, from, to, date...), the the full text body. But, I cannot fetch the body itself. email.message_from_string(response_part[0]) prints mails IDS, and email.message_from_string(response_part[2]) is out of range. email.message_from_string(response_part[1][0]) neither is doing it.

Thanks and regards.

UPDATE

Now, I can almost have body text. However, it is still spoilt by an information statement coming first. I get as a result

From nobody Tue Dec 25 11:42:58 2012

US=3D$4.030

EastCst=3D$4.036

NewEng=3D$4.205

CenAtl=3D$4.149

LwrAtl=3D$3.921

Midwst=3D$3.984

GulfCst=3D$3.945

RkyMt=3D$4.195

WCst=3D$4.187

CA=3D$4.268

and I would like to get rid of From nobody Tue Dec 25 11:42:58 2012 which is information. I know I could parse text look for first relevant line... i know.

The code for achieving so (to plug in my first sample) is

  if varSubject[0] == '$':
      r, d = m.fetch(emailid, "(UID BODY[TEXT])")
      msg_cnt += 1
      my_msg.append(msg)
      print email.message_from_string(d[0][1])

Do you have a better way (no info string) ??? More: what is the command to now fetch the date ? I know that I can do varDate = msg['date'] where suited above, but how to just fetch day-month-year ? THANKS

解决方案

You can get the contents of the body by doing any of the following

msg.as_string()
str(msg)
repr(msg)

http://docs.python.org/2.7/library/email.message.html#email.message.Message

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