'list' 对象在遍历 WebElements 时没有属性 'get_attribute' [英] 'list' object has no attribute 'get_attribute' while iterating through WebElements

问题描述

我正在尝试使用 Python 和 Selenium 来抓取网页上的多个链接.我正在使用 find_elements_by_xpath 并且我能够找到一个元素列表，但是我无法更改返回到实际 href 链接的列表.我知道 find_element_by_xpath 有效，但这只对一个元素有效.

这是我的代码:

path_to_chromedriver = 'chromedriver 位置的路径'浏览器 = webdriver.Chrome(executable_path = path_to_chromedriver)browser.get("file:///html 文件的路径")all_trails = []#找到所有具有text-truncate trail-name"类的元素，然后#获取a元素#这似乎只是给了我们元素位置而不是#实际位置find_href = browser.find_elements_by_xpath('//div[@class="text truncate trail-name"]/a[1]')all_trails.append(find_href)打印 all_trails

此代码正在返回:

,<selenium.webdriver.remote.webelement.WebElement(会话=dd178d79c66b747696c5d3750ea8cb17"，元素="0.5700549730549636-1664")>,

我希望 all_trails 数组是一个链接列表，例如:www.google.com、www.yahoo.com、www.bing.com.>

我尝试遍历 all_trails 列表并在列表上运行 get_attribute('href') 方法，但出现错误:

有人知道如何将 selenium WebElement 转换为 href 链接吗?

任何帮助将不胜感激:)

解决方案

让我们看看您的代码发生了什么:

对相关 HTML 没有任何可见性，似乎以下行将两个 WebElements 返回到 List find_href 依次附加到 all_trails List :

find_href = browser.find_elements_by_xpath('//div[@class="text truncate trail-name"]/a[1]')

因此，当我们打印 List all_trails 时，WebElements 都会被打印出来.因此没有错误.

根据您提供的错误快照，您正在尝试通过 List 调用 get_attribute("href") 方法不支持.因此你会看到错误:

'List' 对象没有属性 'get_attribute'

解决方案:

要获得 href 属性，我们必须遍历 List 如下:

find_href = browser.find_elements_by_xpath('//your_xpath')对于 find_href 中的 my_href:打印(my_href.get_attribute(href"))

I'm trying to use Python and Selenium to scrape multiple links on a web page. I'm using find_elements_by_xpath and I'm able to locate a list of elements but I'm having trouble changing the list that is returned to the actual href links. I know find_element_by_xpath works, but that only works for one element.

Here is my code:

path_to_chromedriver = 'path to chromedriver location'
browser = webdriver.Chrome(executable_path = path_to_chromedriver)

browser.get("file:///path to html file")

all_trails = []

#finds all elements with the class 'text-truncate trail-name' then 
#retrieve the a element
#this seems to be just giving us the element location but not the 
#actual location

find_href = browser.find_elements_by_xpath('//div[@class="text truncate trail-name"]/a[1]')
all_trails.append(find_href)

print all_trails

This code is returning:

<selenium.webdriver.remote.webelement.WebElement 
(session="dd178d79c66b747696c5d3750ea8cb17", 
element="0.5700549730549636-1663")>, 
<selenium.webdriver.remote.webelement.WebElement 
(session="dd178d79c66b747696c5d3750ea8cb17", 
element="0.5700549730549636-1664")>,

I expect the all_trails array to be a list of links like: www.google.com, www.yahoo.com, www.bing.com.

I've tried looping through the all_trails list and running the get_attribute('href') method on the list but I get the error:

Does anyone have any idea how to convert the selenium WebElement's to href links?

Any help would be greatly appreciated :)

解决方案

Let us see what's happening in your code :

Without any visibility to the concerned HTML it seems the following line returns two WebElements in to the List find_href which are inturn are appended to the all_trails List :

find_href = browser.find_elements_by_xpath('//div[@class="text truncate trail-name"]/a[1]')

Hence when we print the List all_trails both the WebElements are printed. Hence No Error.

As per the error snap shot you have provided, you are trying to invoke get_attribute("href") method over a List which is Not Supported. Hence you see the error :

'List' Object has no attribute 'get_attribute'

Solution :

To get the href attribute, we have to iterate over the List as follows :

find_href = browser.find_elements_by_xpath('//your_xpath')
for my_href in find_href:
    print(my_href.get_attribute("href"))

这篇关于'list' 对象在遍历 WebElements 时没有属性 'get_attribute'的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！