Python:“超级"对象没有属性"attribute_name" [英] Python: 'super' object has no attribute 'attribute_name'

问题描述

我正在尝试从基类访问变量.这是父类:

I am trying to access a variable from the base class. Here's the parent class:

class Parent(object):
    def __init__(self, value):
        self.some_var = value

这是子类:

class Child(Parent):
    def __init__(self, value):
        super(Child, self).__init__(value)

    def doSomething(self):
        parent_var = super(Child, self).some_var

现在，如果我尝试运行以下代码:

Now, if I try to run this code:

obj = Child(123)
obj.doSomething()

我收到以下异常:

Traceback (most recent call last):
  File "test.py", line 13, in <module>
    obj.doSomething()
  File "test.py", line 10, in doSomething
    parent_var = super(Child, self).some_var
AttributeError: 'super' object has no attribute 'some_var'

我做错了什么?在Python中从基类访问变量的推荐方法是什么?

What am I doing wrong? What is the recommended way to access variables from the base class in Python?

推荐答案

在运行基类的__init__之后，派生对象在此处设置了属性(例如some_var)，因为它是与在派生类的__init__中.您可以并且应该在任何地方都使用self.some_var. super用于访问基类中的内容，但是实例变量(如名称所示)是实例的一部分，而不是该实例的类的一部分.

After the base class's __init__ ran, the derived object has the attributes set there (e.g. some_var) as it's the very same object as the self in the derived class' __init__. You can and should just use self.some_var everywhere. super is for accessing stuff from base classes, but instance variables are (as the name says) part of an instance, not part of that instance's class.

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