Express-js 通配符路由以覆盖路径下和包括路径下的所有内容 [英] Express-js wildcard routing to cover everything under and including a path

问题描述

我试图让一条路线覆盖 /foo 下的所有内容，包括 /foo 本身.我试过使用 /foo* 它适用于所有除了它不匹配 /foo.观察:

I'm trying to have one route cover everything under /foo including /foo itself. I've tried using /foo* which work for everything except it doesn't match /foo. Observe:

var express = require("express"),
    app = express.createServer();

app.get("/foo*", function(req, res, next){
  res.write("Foo*
");
  next();
});

app.get("/foo", function(req, res){
  res.end("Foo
");
});

app.get("/foo/bar", function(req, res){
  res.end("Foo Bar
");
});

app.listen(3000);

输出:

$ curl localhost:3000/foo
Foo
$ curl localhost:3000/foo/bar
Foo*
Foo Bar

我有哪些选择?我想出的最好方法是路由 /fo* 这当然不是最佳选择，因为它会匹配太多.

What are my options? The best I've come up with is to route /fo* which of course isn't very optimal as it would match way too much.

推荐答案

我认为您必须有 2 条路线.如果您查看连接路由器的第 331 行，路径中的 * 将替换为 .+，因此将匹配 1 个或多个字符.

I think you will have to have 2 routes. If you look at line 331 of the connect router the * in a path is replaced with .+ so will match 1 or more characters.

https://github.com/senchalabs/connect/blob/master/lib/middleware/router.js

如果您有 2 条路线执行相同的操作，您可以执行以下操作来保持它DRY.

If you have 2 routes that perform the same action you can do the following to keep it DRY.

var express = require("express"),
    app = express.createServer();

function fooRoute(req, res, next) {
  res.end("Foo Route
");
}

app.get("/foo*", fooRoute);
app.get("/foo", fooRoute);

app.listen(3000);

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