Express-js通配符路由以覆盖并包含路径的所有内容 [英] Express-js wildcard routing to cover everything under and including a path

问题描述

我试图让一条路线覆盖 / foo 下的所有内容，包括 / foo 本身。我尝试使用 / foo * ，它适用于所有的，除了它不匹配 / foo 。观察：

I'm trying to have one route cover everything under /foo including /foo itself. I've tried using /foo* which work for everything except it doesn't match /foo. Observe:

var express = require("express"),
    app = express.createServer();

app.get("/foo*", function(req, res, next){
  res.write("Foo*\n");
  next();
});

app.get("/foo", function(req, res){
  res.end("Foo\n");
});

app.get("/foo/bar", function(req, res){
  res.end("Foo Bar\n");
});

app.listen(3000);

输出：

$ curl localhost:3000/foo
Foo
$ curl localhost:3000/foo/bar
Foo*
Foo Bar

我有什么选择？我想出的最好的方法是路由 / fo * ，这当然不是最佳的，因为它会匹配很多。

What are my options? The best I've come up with is to route /fo* which of course isn't very optimal as it would match way to much.

推荐答案

我想你必须有2条路线。如果您查看连接路由器的第331行，路径中的*将被替换为+，所以将匹配1个或更多个字符。

I think you will have to have 2 routes. If you look at line 331 of the connect router the * in a path is replaced with .+ so will match 1 or more characters.

https://github.com/senchalabs/connect/blob/master/lib/middleware/router.js

如果您有两条执行相同操作的路线，您可以执行以下操作来保持DRY。

If you have 2 routes that perform the same action you can do the following to keep it DRY.

var express = require("express"),
    app = express.createServer();

function fooRoute(req, res, next) {
  res.end("Foo Route\n");
}

app.get("/foo*", fooRoute);
app.get("/foo", fooRoute);

app.listen(3000);

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