如何强制我的应用程序只打开一个 exe?qt, linux [英] How to force my application to open one exe only? qt, linux

问题描述

我希望我的应用程序只打开一个进程，即如果一个进程已经打开并且用户想再次打开 exe - 它不会打开另一个进程.

I want my application to open only one process, i.e. if the one process is already opened and the user want to open the exe again - it won't open another process.

我如何在 Qt - linux 中做到这一点?

how can I do it in Qt - linux?

10 倍！

推荐答案

您正在寻找的是 QtSingleApplication.

What you're looking for is QtSingleApplication.

如果您启动应用程序的另一个实例，第一个实例甚至会收到通知(您可以传递您想要的任何数据结构).

If you start another instance of your application, the first one will even get notified about it (you can pass whatever data structure you want).

每当另一个实例启动时，我都会使用它来将现有应用程序置于最前面.

I used it to bring the existing application to the front whenever another instance is started.

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