两个字典的合并和求和 [英] Merge and sum of two dictionaries

问题描述

我在下面有一本字典，我想添加到另一本不一定具有不同元素的字典中并合并它的结果.是否有任何内置功能，或者我需要自己制作?

I have a dictionary below, and I want to add to another dictionary with not necessarily distinct elements and merge it's results. Is there any built-in function for this, or will I need to make my own?

{
  '6d6e7bf221ae24e07ab90bba4452267b05db7824cd3fd1ea94b2c9a8': 6,
  '7c4a462a6ed4a3070b6d78d97c90ac230330603d24a58cafa79caf42': 7,
  '9c37bdc9f4750dd7ee2b558d6c06400c921f4d74aabd02ed5b4ddb38': 9,
  'd3abb28d5776aef6b728920b5d7ff86fa3a71521a06538d2ad59375a': 15,
  '2ca9e1f9cbcd76a5ce1772f9b59995fd32cbcffa8a3b01b5c9c8afc2': 11
}

字典中的元素个数也是未知的.

The number of elements in the dictionary is also unknown.

如果合并考虑两个相同的键，则应将这些键的值相加而不是覆盖.

Where the merge considers two identical keys, the values of these keys should be summed instead of overwritten.

推荐答案

你没有说你想要合并的确切方式，所以请选择:

You didn't say how exactly you want to merge, so take your pick:

x = {'both1': 1, 'both2': 2, 'only_x': 100}
y = {'both1': 10, 'both2': 20, 'only_y': 200}

print {k: x.get(k, 0) + y.get(k, 0) for k in set(x)}
print {k: x.get(k, 0) + y.get(k, 0) for k in set(x) & set(y)}
print {k: x.get(k, 0) + y.get(k, 0) for k in set(x) | set(y)}

结果:

{'both2': 22, 'only_x': 100, 'both1': 11}
{'both2': 22, 'both1': 11}
{'only_y': 200, 'both2': 22, 'both1': 11, 'only_x': 100}

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