通过同一键合并两个字典 [英] Merge two dicts by same key

问题描述

我有以下两个玩具字典

d1 = {
 'a': [2,4,5,6,8,10],
 'b': [1,2,5,6,9,12],
 'c': [0,4,5,8,10,21]
 }
d2 = {
 'a': [12,15],
 'b': [14,16],
 'c': [23,35]
  }

我想得到一个唯一的字典，在该字典中，我将第二个字典值堆叠在第一个字典之后，并放在相同的方括号内.

and I would like get a unique dictionary where I stack the second dictionary values after the first ones, within the same square brackets.

我尝试了以下代码

d_comb = {key:[d1[key], d2[key]] for key in d1}

但是我获得的输出在每个键的列表中有两个列表，即

but the output I obtain has two lists within a list for each key, i.e.

{'a': [[2, 4, 5, 6, 8, 10], [12, 15]],
 'b': [[1, 2, 5, 6, 9, 12], [14, 16]],
 'c': [[0, 4, 5, 8, 10, 21], [23, 35]]}

我想获得

{'a': [2, 4, 5, 6, 8, 10, 12, 15],
 'b': [1, 2, 5, 6, 9, 12, 14, 16],
 'c': [0, 4, 5, 8, 10, 21, 23, 35]}

如何用一行或两行代码做到这一点?

How can I do that with a line or two of code?

推荐答案

您几乎拥有了它，而是使用+附加了两个列表:

You almost had it, instead use + to append both lists:

{key: d1[key] + d2[key] for key in d1}

{'a': [2, 4, 5, 6, 8, 10, 12, 15],
 'b': [1, 2, 5, 6, 9, 12, 14, 16],
 'c': [0, 4, 5, 8, 10, 21, 23, 35]}

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