如何将列表转换为以索引为值的字典? [英] How to convert a list to a dictionary with indexes as values?

问题描述

我正在尝试转换以下列表:

l = ['A', 'B', 'C']

到像这样的字典:

d = {'A': 0, 'B': 1, 'C': 2}

我已经尝试过其他帖子的答案，但没有一个对我有用.我现在有以下代码:

d = {l[i]: i for i in range(len(l))}

这给了我这个错误:

不可散列的类型:'list'

解决方案

您可以从内置的 enumerate.你只需要反转索引值映射并使用字典理解来创建字典:

<预><代码>>>>lst = ['A', 'B', 'C']>>>{k: v for v, k in enumerate(lst)}{'A':0，'C':2，'B':1}

I am trying to convert the following list:

l = ['A', 'B', 'C']

To a dictionary like:

d = {'A': 0, 'B': 1, 'C': 2}

I have tried answers from other posts but none is working for me. I have the following code for now:

d = {l[i]: i for i in range(len(l))}

Which gives me this error:

unhashable type: 'list'

解决方案

You can get the indices of a list from the built-in enumerate. You just need to reverse the index-value map and use a dictionary comprehension to create a dictionary:

>>> lst = ['A', 'B', 'C']
>>> {k: v for v, k in enumerate(lst)}
{'A': 0, 'C': 2, 'B': 1}

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