OpenCV 2.2 中的像素访问 [英] Pixel access in OpenCV 2.2

问题描述

我想用 opencv 告诉我一个空白和白色图像的像素值所以输出看起来像这样

Hi I want to use opencv to tell me the pixel values of a blank and white image so the output would look like this

10001
00040
11110   
00100

这是我当前的代码，但我不确定如何访问 CV_GET_CURRENT 调用的结果..有什么帮助吗?

Here is my current code but I'm not sure how to access the results of the CV_GET_CURRENT call.. any help ?

IplImage readpix(IplImage*  m_image) {


  cout << "Image width  : " << m_image->width << "
"; 
  cout << "Image height : " << m_image->height << "
"; 
  cout << "-----------------------------------------
"; 


  CvPixelPosition8u position;

  CV_INIT_PIXEL_POS(position, (unsigned char*)(m_image->imageData), m_image->widthStep, cvSize(m_image->width, m_image->height), 0, 0, m_image->origin);

  for(int y = 0; y < m_image->height; ++y) // FOR EACH ROW
  {
    for(int x = 0; x < m_image->width; ++x) // FOR EACH COL 
      {
        CV_MOVE_TO(position, x, y, 1);
        unsigned char colour = *CV_GET_CURRENT(position, 1);

// I want print 1 for a black pixel or 0 for a white pixel 
// so i want goes here


      }

  cout << " 
"; //END OF ROW

  }
}

推荐答案

在 opencv 2.2 中，我会使用 C++ 接口.

In opencv 2.2, I'd use the C++ interface.

cv::Mat in = /* your image goes here, 
                assuming single-channel image with 8bits per pixel */
for(int row = 0; row < in.rows; ++row) {
    unsigned char* inp  = in.ptr<unsigned char>(row);
    for (int col = 0; col < in.cols; ++col) {
        if (*inp++ == 0) {
            std::cout << '1';
        } else {
            std::cout << '0';
        }
        std::cout << std::endl;
    }
}

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