DropDownList的不改变它的价值 [英] DropDownList doesn't change it's value

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本文介绍了DropDownList的不改变它的价值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的问题是如此灵活,所以我不知道什么是这个问题的正确称号。我会尽量描述清楚我的问题,希望你能理解,如果你不,请询问。

My problem is so flexible, so I dont know what is the right title for this question. I'll try to describe my problem clearly, hope you can understand, if you dont, please ask.

我用一个DropDownList我notice.aspx页面。

I use a DropDownList in my notice.aspx page.

DropDownlist value: 1--> show notice in one day ago; 2--> 7 days ago;3--> 30 days ago.
<asp:DropDownList ID="DropDownListTime" runat="server" OnSelectedIndexChanged="IndexNotice_Changed"
            AutoPostBack="true" >
                <asp:ListItem Selected="True"></asp:ListItem>
                <asp:ListItem Value="1"> 1 day ago  </asp:ListItem>
                  <asp:ListItem Value="2"> 7 days ago </asp:ListItem>
                  <asp:ListItem Value="3"> 30 days ago </asp:ListItem>
            </asp:DropDownList> 

和code在notice.aspx.cs

And code in notice.aspx.cs

   private static string key;
 protected void Page_Load(object sender, EventArgs e)
        { if (!IsPostBack)
            {
                BindData();

            }              
        }

            public void BindData()
            {
             string sql="";
                  if (string.IsNullOrEmpty(DropDownListTime.SelectedValue))
                  {
                      key = "3";
                  }
                  else
                  {
                      key = DropDownListTime.SelectedValue.ToString();
                  }
                  if(key.Equals("1"))
                 {
                      sql="select top 5 notice in 1 day ago...";//show 
                  }
                 if(key.Equals("2"))
                {
                     sql="select top 5 notice in 7 day ago...";
                 }
               if(key.Equals("3"))
                {
                       sql="select top 5 notice in 30 day ago...";
                }
                  Datatable dt= excute(sql);
                    ...
               HyperLink1.NavigateUrl = string.Format("Allnotice.aspx?key={0}",key);// go to page to show all notices with `1 day`,`7days`,`30 days` ago depend on the `key`
        }
 public  void IndexNotice_Changed(Object sender, EventArgs e)
        {
            BindData();
        }

当我点击Hyperlink1,关键是送花儿给人3;所以Allnotice.aspx页面常是显示30天通知书前。

When I click on the Hyperlink1, the key alway is 3; so the Allnotice.aspx page is alway show the notices in 30days ago.

我真的不知道为什么的dropdownlist的值总是3。
是否有我上面的code任何错误,请帮助!

I really dont know why the value of dropdownlist is always 3. Is there any mistake in my code above, please help!!!

更新:

我已经删除了行:私有静态字符串键; 并声明字符串键= BindData()它仍然有效错误的。

I've deleted the line: private static string key; and declare string key="" in BindData() it still works wrong.

似乎有与 DropDownListTime.SelectedValue 没有问题。当我调试,我看到了可变密钥是正确的(我的意思是这是正确的与我选用的时间)。但是,当我点击超链接时,地址栏是显示键= 3

It seems there is no problem with DropDownListTime.SelectedValue. When I debug, I saw the variable key is right (I mean it is right with the time I choosed). But when I click on the Hyperlink, the addressbar is show the key=3.

帮助!

推荐答案

在初始页面加载,关键将永远是3.作为结果,超链接的关键是3。

On initial page load, the key will always be 3. As the result, hyperlink's key is 3.

一旦你选择的DropDownList一个新值,超链接的键将改变你选择的任何值。

Once you select a new value in DropDownList, the hyperlink's key will change to whatever value you selected.

我注意到的是,你不应该在你的场景中使用静态值。

private static string key;

删除上面的行,并将其移动内部 BindData()

public void BindData()
{
    string key;
    string sql = "";
    if (string.IsNullOrEmpty(DropDownListTime.SelectedValue))
    {
        key = "3";
    }
    ...
}

这篇关于DropDownList的不改变它的价值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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