对 UITableView 使用 didSelectRowAtIndexPath 或 prepareForSegue 方法? [英] Use didSelectRowAtIndexPath or prepareForSegue method for UITableView?

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本文介绍了对 UITableView 使用 didSelectRowAtIndexPath 或 prepareForSegue 方法?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用故事板并且我有一个 UITableView.我有一个 segue 设置,可以从我的表推送到详细信息 VC.但是我应该使用哪种方法来处理这个问题?我必须将几个对象传递给详细信息视图.但是我是使用 didSelectRowAtIndex 还是 -(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender?

I'm using storyboards and I have a UITableView. I have a segue setup that pushes from my table to the detail VC. But which method should I use to handle this? I'll have to pass a couple objects to the detail view. But do I use didSelectRowAtIndex or -(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender?

推荐答案

如果您使用 prepareForSegue:sender: 那么如果您以后决定从表视图之外的一些控件.

If you use prepareForSegue:sender:then you won't have as much to change if you later decide to trigger the segue from some control outside the table view.

prepareForSegue:sender: 消息被发送到当前视图控制器,所以我建议如下:

The prepareForSegue:sender: message is sent to the current view controller, so I'd suggest something like this:

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    // Assume self.view is the table view
    NSIndexPath *path = [self.tableView indexPathForSelectedRow];
    DetailObject *detail = [self detailForIndexPath:path];
    [segue.destinationViewController setDetail:detail];
}

在 Swift 中:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    let path = self.tableView.indexPathForSelectedRow()!
    segue.destinationViewController.detail = self.detailForIndexPath(path)
}

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