对UITableView使用didSelectRowAtIndexPath或prepareForSegue方法? [英] Use didSelectRowAtIndexPath or prepareForSegue method for UITableView?
问题描述
我正在使用故事板,我有一个UITableView。我有一个segue设置,从我的表推送到详细VC。但是我应该使用哪种方法来处理这个问题?我必须将几个对象传递给详细视图。但我是否使用 didSelectRowAtIndex
或 - (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
?
如果你使用 prepareForSegue:sender:
那么你就不会如果你以后决定从表格视图之外的某些控件触发segue,那就要改变了。
prepareForSegue:sender:
消息被发送到当前视图控制器,所以我建议这样的事情:
- (void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
//假设self.view是表视图
NSIndexPath * path = [self.tableView indexPathForSelectedRow];
DetailObject * detail = [self detailForIndexPath:path];
[segue.destinationViewController setDetail:detail];
}
在Swift中:
< pre class =lang-swift prettyprint-override>
覆盖func prepareForSegue(segue:UIStoryboardSegue,sender:AnyObject?){
let path = self.tableView.indexPathForSelectedRow()!
segue.destinationViewController.detail = self.detailForIndexPath(path)
}
I'm using storyboards and I have a UITableView. I have a segue setup that pushes from my table to the detail VC. But which method should I use to handle this? I'll have to pass a couple objects to the detail view. But do I use didSelectRowAtIndex
or -(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
?
If you use prepareForSegue:sender:
then you won't have as much to change if you later decide to trigger the segue from some control outside the table view.
The prepareForSegue:sender:
message is sent to the current view controller, so I'd suggest something like this:
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
// Assume self.view is the table view
NSIndexPath *path = [self.tableView indexPathForSelectedRow];
DetailObject *detail = [self detailForIndexPath:path];
[segue.destinationViewController setDetail:detail];
}
In Swift:
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
let path = self.tableView.indexPathForSelectedRow()!
segue.destinationViewController.detail = self.detailForIndexPath(path)
}
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