拆分路径并在批处理脚本中取最后一个文件夹名称 [英] split path and take last folder name in batch script

问题描述

我想用 拆分字符串(具有路径)并在变量中取最后一个文件夹名称.请帮忙.

I want to split the string (having a path) with and take last folder name in a variable. Please help.

例如
mypath=D:FOLDER1FOLDER2FOLDER3

e.g
mypath=D:FOLDER1FOLDER2FOLDER3

我想要一个变量中的 FOLDER3.

I want FOLDER3 in a variable.

我尝试使用下面的命令，如果最后一个字符不是 :

I tried with the command below which is working if the the last character is not :

for %f in (C:FOLDER1FOLDER2FOLDER3) do set myfolder=%~nxf

如果最后一个字符是

如果像这样使用变量，它也不起作用:对于 (%mypath%) 中的 %f 设置 myfolder=%~nxf

Also it is not working if variable is used like : for %f in (%mypath%) do set myfolder=%~nxf

推荐答案

@echo off

set MYDIR=C:FOLDER1FOLDER2FOLDER3
set MYDIR1=%MYDIR:~0,-1%

for %%f in (%MYDIR1%) do set myfolder=%%~nxf
echo %myfolder%

输出

FOLDER3

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